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likoan [24]
2 years ago
7

The following histogram shows the theoretical probability of the number of heads you might get after flipping for coins simultan

eously. If you were to flip four coins what is the probability that you get a two or more coins that land heads up?

Mathematics
2 answers:
Ghella [55]2 years ago
8 0

Answer:

(0.25x)+0.25)=50

Step-by-step explanation:

you could multiply 0.25 by 2 or add 0.25 by the same number.

aleksandr82 [10.1K]2 years ago
3 0

Answer:

i think this is how you find it but i apologize if im wrong

Step-by-step explanation:

Use binomial probability since there are only two possibilities: success and failure, where success represents getting a heads, and tails being a fail. Therefore we are trying to find P(X=2), which is (42)⋅(0.5)2⋅(0.5)2=0.375.

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20-30=-10

[(-10+10)+10+10]=20

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Y&lt; 3x + 6<br> Determine if (2,4) is a solution
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Answer:

Yes

Step-by-step explanation:

4 < 3(2) + 6

4< 6+6

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A blizzard occurred on the East Coast during January, 2016. Snowfall totals from the storm
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Look at number 3 for the answer

7 0
2 years ago
K is the midpoint of JL. JK = 2x + 5 and JL = 50.
Sergeu [11.5K]
Steve set the equation equal to 50 which is the entire length of JL. instead he should've set the equation equal to 25, since it's half of 50 and would represent the midpoint. he should've said 2x + 5 = 25
8 0
2 years ago
A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud
iris [78.8K]

Answer:

-0.048

Do not reject  H_0:P_1-P_2=0

Step-by-step explanation:

From the question we are told that

Sample size n_1=350

Sample size n_2=250

Sample proportion 1  \hat P= \frac{25}{350} =>0.07

Sample proportion 2 \hat P= \frac{19}{250} =>0.076

95% confidence interval

Generally for 95% confidence level

Level of significance

 \alpha = 1-0.95=>0.05

 \alpha /2=\frac{0.05}{2} =>0.025

Therefore

Z_a_/_2=1.96

Generally the equation for confidence interval between P_1 - P_2  is mathematically given as

(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2}  }

(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250}  }

(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4  }

(-0.006)\pm 0.042

(-0.006)- 0.042=>-0.048

(-0.006)+ 0.042=>0.036

Therefore

Confidence interval is

-0.048

Conclusion

Given the confidence interval has zero

Therefore do not reject  H_0:P_1-P_2=0

6 0
2 years ago
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