This is your answer:
<span>Trapezoid
JKLM is congruent to trapezoid J′K′L′M′ because you can map trapezoid
JKLM to trapezoid J′K′L′M′ by reflecting it across the line y = x and
then translating it 1 unit up, which is a sequence of rigid motions.</span>
A1 = 4
a2 = 5a1 = 5 x 4 = 20
a3 = 5a2 = 5 x 20 = 100
a4 = 5a3 = 5 x 100 = 500
a5 = 5a4 = 5 x 500 = 2,500
Tn = ar^(n-1); where a = 4, r = 5
Tn = 4(5)^(n-1) = 4/5 (5)^n
Explicit formular is Tn = 4/5 (5)^n
Recursive formular is
Answer:
Step-by-step explanation:
No, the equation cannot be written with the given information. The distance from the catapult when the watermelon reached the maximum height is needed. Since the watermelon did not start on the ground, it cannot be assumed that the maximum was reached half the distance to the landing point.
Answer: Oh the answer is 30.00
Step-by-step explanation: