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3 years ago

10

PLEASE HELP PLEASE PLEASE

1 answer:

Alex3 years ago

7 0

Answer:

The second one is d. 13

Step-by-step explanation:

Add what you know first. 110+57= 167. Then, subtract what the angle is all together with the answer from what you know. 180-167= 13. X= 13. I'm bad at explaining so I hope that was clear.

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Please answer number 4 and 5

Anestetic [448]

Answer: 4=G 5=A

Step-by-step explanation:

4: since he has only 1 dime 2 nickels and 1 quarter he cant pull out 2 dimes since he doesn't have them, meaning G is not possible.

5: To solve you have to multiply 2 1/2 and 3 1/4, one way is by creating improper fractions and multiply that way. So you will get 5/2 x 13/4 which will give you 65/8. Simply to get 8 and 1/8

4 0

3 years ago

I need help with this

Effectus [21]

Answer:

The answer is B

Step-by-step explanation:

5 0

3 years ago

Look at the attached photo

Papessa [141]

Answer:

Step-by-step explanation:

radius of the circle=12 cm / 2=6 cm

Area of the square=side²=(12 cm)²=144 cm²

Area of the circle=πr²=(3.142)(6 cm)²≈(3.142)*36 cm²≈113.112 cm²

Area of the four sides between the square and the circle=

=Area of the square - area of the circle=144 cm²-113.112 cm²=30.888 cm²

shaded area =30.888 cm²/4=7.722 cm²

Answer =7.722 cm²

6 0

3 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

3 years ago

What is the solution to this equation?<br> x-8=15<br><br> A)x=13<br> B)x=17<br> C)x=7<br> D) x=23

Blababa [14]

Hi there! :)

<u><em>Answer:</em></u>

<u><em>x=23</em></u>

<u><em>*The answer must have a positive sign.*</em></u>

Step-by-step explanation:

This lesson it's about addition property of equality.

First, you add by 8 from both sides of an equation.

$x-8+8=15+8$

And then, you add by the numbers. Simplify and solve.

$15+8=23$

Final answer: → $x=23$

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

3 0

3 years ago