Answer:
0.295 g Co
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
3.01 × 10²¹ atoms Co
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Co - 58.93 g/mol
<u>Step 3: Convert</u>
<u /> = 0.294552 g Co
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
0.294552 g Co ≈ 0.295 g Co
Answer:
The mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.351 %.
Explanation:
Given,
Mass of Sucrose = 7.6 grams
Mass of Water = 83.4 grams
In this solution, Sucrose is solute and water is the solvent.
Mass percent of a solution can be calculated using the formula,
Mass percent = (Mass of Solute/Mass of Solution)(100)
As sucrose is solute, mass of solute = 7.6 grams
As the solution contains both Sucrose and Water,
Mass of solution = 7.6 grams + 83.4 grams = 91 grams
Substituting the values, Mass percent = (7.6/91)(100) = 8.351 %.
C because a series circuit only has one loop so it’s C
According to Dalton's law of partial pressure
The total pressure of a mixture of ideal gases is sum of the partial pressures of each gas present in the mixture
So if we know the partial pressure of all the gases we can determine the total pressure of the mxiture by adding all of them.
Thus
Ptotal = PCl2 + PF2 + PHe
Thus
Partial pressure of helium = 205 - ( 89 + 15) = 101 kPa