The velocity of the two-car train is 3.5 m/s.
To solve the problem above, we use the law of conservation of momentum
Law of conservation of momentum: States that, for a closed system, the total momentum before collision is equal to the total momentum after collision.
⇒ Formula:
mu+m'u' = V(m+m')..................... Equation 1
⇒ Where:
- m = mass of the faster train
- m' = mass of the slower train
- u = initial velocity of the faster train
- u' = initial velocity of the slower train
- V = common velocity of the two trains
⇒ make V the subject of the equation
- V = (mu+m'u')/(m+m')....................... Equation 2
From the question,
⇒ Given:
- m = 2500 kg
- m' = 1500 kg
- u = 5 m/s
- u' = 1 m/s
⇒ Substitute these values into equation 2
- V = [(2500×5)+(1500×1)]/(2500+1500)
- V = [12500+1500]/(4000)
- V = 14000/4000
- V = 3.5 m/s.
Hence, The velocity of the two-car train is 3.5 m/s
Learn more about the law of conservation of momentum: brainly.com/question/9408577
It makes a cycloid pattern in parametrics if that's what you're asking~
Convert 1 atom into 10 electrons (I think)
Answer:
The term significant figures refers <em>to the number of important single digits (0 through 9 inclusive) in the coefficient of an expression in scientific notation. </em>
Hope its helpful!
#1
so mass number = 238
mass number = protons + neutrons
given that
neutrons = 146
238 = protons + 146
protons = 92
#2
so mass number = 241
mass number = protons + neutrons
given that
Protons = 94
241 = 94 + neutrons
neutrons = 147
#3
A = mass number
Protons = 90
Neutrons = 137
A = protons + Neutrons
A = 90 + 137 = 227