The value was determined to be 0.122 m/s. The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form.
Velocity is essentially a vector quantity. It is the rate of change in distance. The initial speed of the first train, which has a mass of 150,000 kg, is 0.3 m/s. The second train has an initial speed of -0.120 m/s and a mass of 110,000 kg.
Let v represent the post-collision speed of the connected mass.
Utilize the idea of momentum.
The speed of the trains is constant both before and after a collision.
150.000 + 110.000v 45.000 - 13200 = 260.000 v 31800 = 260.000 v v = 0.122 m/s 150000 x 0.3 - 110000 x 0.120
After colliding, they move at a speed of 0.122 m/s towards the direction of the right.
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Answer:
The minimum speed must the car must be 13.13 m/s.
Explanation:
The radius of the loop is 17.6 m. We need to find the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top.
We know that, mg be the weight of car and rider, which is equal to the centripetal force.
So, the minimum speed must the car must be 13.13 m/s.
Answer
Factors Affecting Acceleration Due to Gravity
(1) Position on the planetary surface, it is higher at the axis (poles),
(2) Mass of the planet, higher with planets of larger masses
(3) Distance between object and the centre of planet, the larger the distance, the smaller the acceleration due to gravity.
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Answer:
the rigid outer part of the earth, consisting of the crust and upper mantle.
Explanation:
