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denis23 [38]
3 years ago
6

How can you calculate the number of electrons in an atom

Physics
2 answers:
Serga [27]3 years ago
7 0
Convert 1 atom into 10 electrons (I think)
Gelneren [198K]3 years ago
6 0
The atomic number( number in the top left corner of the element’s box on the Periodic Table)
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Water falls off a cliff of height 20m at a rate of 50kg per second
docker41 [41]

Answer:

M = 50 kg / sec * 60 sec = 3000 kg       water that falls

PE = M g h     initial potential energy of water

PE = 3000 kg * 9.8 m/s^2 * 20 m = 588,000 joules of energy lost

5 0
2 years ago
Consider that 168.0 J of work is done on a system and 305.6 J of heat is extracted from the system. In the sense of the first la
Ilia_Sergeevich [38]

To solve this problem we must resort to the Work Theorem, internal energy and Heat transfer. Summarized in the first law of thermodynamics.

dQ = dU + dW

Where,

Q = Heat

U = Internal Energy

By reference system and nomenclature we know that the work done ON the system is taken negative and the heat extracted is also considered negative, therefore

W = -168J \righarrow  Work is done ON the system

Q = -305.6J \rightarrow Heat is extracted FROM the system

Therefore the value of the Work done on the system is -158.0J

3 0
3 years ago
A man is walking while riding a train. He says he is moving at 2 mph. A woman standing on a platform at a train station says the
Semenov [28]

The woman on the platform is correct because it is the pace of the man moving on the train not walking.

6 0
3 years ago
Kathy 82 kg performer standing on a diving board at the carnival dive straight down into a small pool of water. Just before stri
mixas84 [53]

Solution :

Given weight of Kathy = 82 kg

Her speed before striking the water, $V_o $ = 5.50 m/s

Her speed after entering the water, $V_f$= 1.1 m/s

Time = 1.65 s

Using equation of impulse,

$dP = F \times  dT$

Here, F =  the force ,

       dT =  time interval over which the force is applied for

            = 1.65 s

       dP  = change in momentum

dP = m x dV

    $= m \times [V_f - V_o] $

    = 82 x (1.1 - 5.5)

    = -360 kg

∴ the net force acting will be

$F=\frac{dP}{dT}$

$F=\frac{-360}{1.65}$

  = 218 N

8 0
3 years ago
A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.
Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

F=mg

\dfrac{mv^2}{r}=mg

\dfrac{v^2}{r}=g

v=\sqrt{rg}

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

v=\sqrt{250\times9.8}

v=49.49\ m/s

Hence, The speed of space station floor is 49.49 m/s.

6 0
3 years ago
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