Explanation:
A force that leads to movement of an object is known as work.
The energy present in an object due to its position in a gravitational field is known as gravitational potential energy.
Kinetic energy is the energy obtained by an object due to its motion.
For example, when Jerome is swinging on a rope then there occurs movement in the swing due to which the swing has kinetic energy.
Since, a force has been applied on the swing to make it move. Hence, a work is also done.
Therefore, we can conclude that if Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, work is being done.
Answer;
-A model
Explanation;
-A mathematical model is an abstract model that uses mathematical language to describe the behavior of a system. A Mathematical Model tries to copy how a real world thing works using equations.
-Usually a mathematical model describes a system by a set of variables and a set of equations that establish relationships between the variables. Variables may be of many types; real or integer numbers, for example.
-The Area A of a circle with radius r is given by the formula A = πr2. In this formula π ≈ 3.1416... is a number which is a constant, and A and r are variables or unknowns. A is called the subject of the formula.
The answer to this question is "LIES BELOW THE SURFACE" happens or occurs. When one of the main differences between the two which is the Intaglio and the other one is the relief printing processes is that with the Intaglio the ink LIES BELOW the surface of the printing plate.
Answer:
28.5 m/s
18.22 m/s
Explanation:
h = 20 m, R = 20 m, theta = 53 degree
Let the speed of throwing is u and the speed with which it strikes the ground is v.
Horizontal distance, R = horizontal velocity x time
Let t be the time taken
20 = u Cos 53 x t
u t = 20/0.6 = 33.33 ..... (1)
Now use second equation of motion in vertical direction
h = u Sin 53 t - 1/2 g t^2
20 = 33.33 x 0.8 - 4.9 t^2 (ut = 33.33 from equation 1)
t = 1.17 s
Put in equation (1)
u = 33.33 / 1.17 = 28.5 m/s
Let v be the velocity just before striking the ground
vx = u Cos 53 = 28.5 x 0.6 = 17.15 m/s
vy = uSin 53 - 9.8 x 1.17
vy = 28.5 x 0.8 - 16.66
vy = 6.14 m/s
v^2 = vx^2 + vy^2 = 17.15^2 + 6.14^2
v = 18.22 m/s
