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4 years ago

HELP ASAP---

Biology

2 answers:

lilavasa [31]4 years ago

8 0

The answer is A) i believe..

zvonat [6]4 years ago

6 0

Answer:

the correct answer is

A:heat energy radiates towards the atmosphere, energy gets recycled before escaping into space

the rest are incorrect

Explanation:

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A small town in the piney woods of East Texas has a soccer field composed of native grasses. The soccer field is mowed once a we

Andreas93 [3]

Explanation:

D) Mowing maintains a low species diversity by inhibiting succession.

Mowing reduces the chances of growth of a new species within the community that may add to its complexity.

Succession involves small scale changes within a community that occur repeatedly over the life of that community. Ecological communities are highly dynamic- they gradually evolve. Typically their progression involves:

colonizing species exploiting uninhabited areas (Primary succession)
becoming a habitable and increasingly complex community
there is increased diversity of organisms (Secondary)

Further Explanation:

The makeup of biological communities is crucial to defining Primary and Secondary succession; eventually, through changes in this makeup, a steady-state or equilibrium is reached called a climax community. While Primary succession starts off with the modification of a previously unoccupied area along with increasing variation; secondary succession begins after major disruption in the community such as fires, storms and flooding.

However, the process of becoming a climax community can be pretty complicated- it is very dependent on other factors like temperature and rainfall. Communities that experience rapid change, frequent major disruptions and even human intervention, are less likely to attain a stable equilibrium and may never become climax communities.

Learn more about ecological succession at brainly.com/question/2456852

#LearnWithBrainly

5 0

4 years ago

Does anybody know what homeostasis is, and what specific definition, and details of what happens to homeostasis if it had energy

tankabanditka [31]

Answer: homeostasis: is the ability to maintain a constsant body temperature

Explanation: im not sure what you mean by if it had energy homeostasis deals with body temperature not energy but i guess someone can follow me up on this

8 0

3 years ago

Read 2 more answers

The ______ delivers oxygen-rich blood to the thick heart wall while the ______ carries the deoxygenated blood away from the hear

DiKsa [7]

Explanation:

first blank is; Mitral valve.

2nd blank is; Left Ventricle

5 0

2 years ago

Waste products which build up in the body can become deadly.<br><br> True or False

worty [1.4K]

This is true. There are many complications that could stem from excess waste products in the body.

5 0

3 years ago

Read 2 more answers

Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0

3 years ago