Answer:2.5×10^-5. (And i think u meant in Scientific Notation)
Step-by-step explanation//Give thanks(and or Brainliest) if helpful (≧▽≦)//
Answer:
-37/100
Step-by-step explanation:
Here, we want to write -0.37 as a quotient of integers
What we are saying is that we want to write it as a fraction of two numbers
That would be;
-0.37 = -37/100
First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
![d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }](https://tex.z-dn.net/?f=d%20%3D%20%20%5Csqrt%7B%7B%28y2%20-%20y1%29%7D%5E%7B2%7D%20%2B%20%7B%28x2%20-%20x1%29%7D%5E%7B2%7D%20%7D%20)
![d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3](https://tex.z-dn.net/?f=d1%20%3D%20%20%5Csqrt%7B%7B%281%20-%204%29%7D%5E%7B2%7D%20%2B%20%7B%28%20-%202%20-%20%20-%202%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%7B%28-%203%29%7D%5E%7B2%7D%20%2B%20%7B%280%29%7D%5E%7B2%7D%20%7D%20%3D%20%20%5Csqrt%7B9%7D%20%20%5C%3A%20%3D%203)
![d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5](https://tex.z-dn.net/?f=d2%20%3D%20%5Csqrt%7B%7B%284%20-%207%29%7D%5E%7B2%7D%20%2B%20%7B%28%20-%202%20-%202%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%5Csqrt%7B%7B%28-%203%29%7D%5E%7B2%7D%20%2B%20%7B%28%20-4%29%7D%5E%7B2%7D%20%7D%20%3D%20%20%5Csqrt%7B9%20%2B%2016%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B25%7D%20%20%5C%3A%20%3D%205)
![d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5](https://tex.z-dn.net/?f=d3%20%5C%3A%20%3D%20%5Csqrt%7B%7B%287%20-%204%29%7D%5E%7B2%7D%20%2B%20%7B%282%20-%206%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%7B%283%29%7D%5E%7B2%7D%20%2B%20%20%7B%28%20-%204%29%7D%5E%7B2%7D%20%7D%20%3D%20%20%5Csqrt%7B9%20%2B%2016%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B25%7D%20%5C%3A%20%20%3D%205)
![d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3](https://tex.z-dn.net/?f=d4%20%3D%20%5Csqrt%7B%7B%284%20-%201%29%7D%5E%7B2%7D%20%2B%20%7B%286%20-%206%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%20%7B%283%29%7D%5E%7B2%7D%20%2B%20%20%7B%280%29%7D%5E%7B2%7D%20%20%7D%20%20%3D%20%20%5Csqrt%7B9%7D%20%5C%3A%20%20%3D%203)
![d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4](https://tex.z-dn.net/?f=d5%20%3D%20%5Csqrt%7B%7B%281%20-%201%29%7D%5E%7B2%7D%20%2B%20%7B%28-2%20-%206%29%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%3D%20%20%5Csqrt%7B%20%7B%280%29%7D%5E%7B2%7D%20%2B%20%20%7B%28%20-%204%29%7D%5E%7B2%7D%7D%20%3D%20%20%5Csqrt%7B16%7D%20%20%5C%3A%20%20%3D%204%20)
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units
The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].
Hope this helps.
Hmmm, I'm guessing your asking if that's correct, if so, yes