At a convention for lawyers it was known that of the 100 present, at least one was honest, yet if you met any two of the lawyers
, you could guarantee that at least one of the two would be crooked. How many honest lawyers were present?
1 answer:
In my opinion there would be fifty one honest lawers
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A B
D C
vectors
AB = DC
AB (-2-7 ; 3-1) => AB (-9 ; 2)
DC (1-x : -7-y)
1 - x = -9 => x = 10
-7-y = 2 => y = -9
D(10 ; -9)
C= 5(9*3b)
C= 5(9*12)
C= 5(108)
C=540
Answer:
A) 0 and 13
Step-by-step explanation:
64 - 37 = 27
27/2 = 13.5
13 teachers can teach 3 classes at max
21 square yards. Length times width (7 times 3) equals 21
