Difference of 2 perfect squares
remember

so
Let's consider the first number to be
and the second number to be
. Based on the information in the problem, we can create the following equations:


Now, we can solve the equations through systems of equations. One way of doing this is by multiplying one of the equations so that there is a term in both equations which can be removed by addition or subtraction. In our case, we can multiply the entire first equation by 2 to get:
![2f + 4s = 2/tex][tex]2f + s = 14](https://tex.z-dn.net/?f=2f%20%2B%204s%20%3D%202%2Ftex%5D%3C%2Fp%3E%3Cp%3E%5Btex%5D2f%20%2B%20s%20%3D%2014)
Now, subtract
from both equations to get:


Now that we have found
, "plug" it back into an equation to find
:



Our answers are s = -4 and f = 9.
Part A: the value of x is 0 because anything to the zero power is 1
part B: x can be any number. 6 to the 0 power is 1 and 1 to any power is 1
No---------------------------------
Answer:
The equation of the line is:
Step-by-step explanation:
The slope-intercept form of the line equation
y = mx+b
where
Given
now substituting b = -12 and m = 3/2 in the slope-intercept form of line equation



Therefore, the equation of the line is: