What are the x-intercepts for y=x2+6x?
1 answer:
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9514 1404 393
Answer:
(1.43, 1.87)
Step-by-step explanation:
The formula for the incenter requires we know the lengths of the sides of the triangle. These are found using the distance formula.
BC = √((4-3)^2 +(5+1)^2) = √37
AC = √((-4-3)^2 +(2+1)^2) = √58
AB = √((-4-4)^2 +(2-5)^2) = √73
Then the incenter is ...
(A(BC) +B(AC) +C(AB))/(BC +AC +AB)
≈ (6.08276(-4, 2) +7.61577(4, 5) +8.54400(3, -1))/22.2425
≈ (1.42808, 1.87480)
Rounded to hundredths, the incenter is (1.43, 1.87).
