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BabaBlast [244]

2 years ago

14

Fill up the blank :- Weight is measured as the downward force of __________.

2 answers:

asambeis [7]2 years ago

6 0

Weight is measured as the downward force of gravity. Gravity is actually considered as the force that attracts all matters towards each other. The more the matter present, the more is the gravitational force involved. I hope that this is the answer that has come to your help.

Makovka662 [10]2 years ago

4 0

<span>Weight is measured as the downward force of gravity.</span>

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Which of the following is most useful to determine how much energy is being used by a circuit in a given amount of time?

user100 [1]

Answer:

The answer is A.

Explanation:

5 0

2 years ago

A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carouse

Sidana [21]

Answer:

m = 35.98 Kg ≈ 36 Kg

Explanation:

I₀ = 125 kg·m²

R₁ = 1.50 m

ωi = 0.600 rad/s

R₂ = 0.905 m

ωf = 0.800 rad/s

m = ?

We can apply The law of conservation of angular momentum as follows:

Linitial = Lfinal

⇒ Ii*ωi = If*ωf <em>(I)</em>

where

Ii = I₀ + m*R₁² = 125 + m*(1.50)² = 125 + 2.25*m

If = I₀ + m*R₂² = 125 + m*(0.905)² = 125 + 0.819025*m

Now, we using the equation <em>(I) </em>we have

(125 + 2.25*m)*0.600 = (125 + 0.819025*m)*0.800

⇒ m = 35.98 Kg ≈ 36 Kg

5 0

3 years ago

Why does a small particle size generally cause a reaction to proceed faster?

Ugo [173]

I think its a. i am not sure though.

7 0

3 years ago

What velocity must a car with a mass of 1110 kg have in order to have the same momentum as a 2280 kg pickup truck traveling at 2

shutvik [7]

Answer:

49.3 m/s

Explanation:

The momentum is defined as the product of the object velocity and its mass.

So the momentum of the truck is

$P_t = 2280 * 24 = 54720 kgm/s$

For the car to have the same momentum, its speed must be

$v_c = P_t/m_c = 54720 / 1110 = 49.3 m/s$

6 0

3 years ago

Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0

DENIUS [597]

Answer:

Tension in the string is equal to 58.33 N ( this will be the strength of the string )

Explanation:

We have given mass m = 1.7 kg

radius of the circle r = 0.48 m $F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N$

Kinetic energy is given 14 J

Kinetic energy is equal to $KE=\frac{1}{2}mv^2$

So $\frac{1}{2}\times 1.7\times v^2=14$

$v^2=16.47$

v = 4.05 m/sec

Centripetal force is equal to $F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N$

So tension in the string will be equal to 58.33 N ( this will be the strength of the string )

3 0

3 years ago