The answer is commensalism because commensalism is a relationship where an organism is benefitted and the other is neither benefitted nor harmed. The barnacle is being benefited and the whale is not being benefited or harmed.
Answer:
8050 J
Explanation:
Given:
r = 4.6 m
I = 200 kg m²
F = 26.0 N
t = 15.0 s
First, find the angular acceleration.
∑τ = Iα
Fr = Iα
α = Fr / I
α = (26.0 N) (4.6 m) / (200 kg m²)
α = 0.598 rad/s²
Now you can find the final angular velocity, then use that to find the rotational energy:
ω = αt
ω = (0.598 rad/s²) (15.0 s)
ω = 8.97 rad/s
W = ½ I ω²
W = ½ (200 kg m²) (8.97 rad/s)²
W = 8050 J
Or you can find the angular displacement and find the work done that way:
θ = θ₀ + ω₀ t + ½ αt²
θ = ½ (0.598 rad/s²) (15.0 s)²
θ = 67.3 rad
W = τθ
W = Frθ
W = (26.0 N) (4.6 m) (67.3 rad)
W = 8050 J
The force is still 1 pound.
The TORQUE around the pivot is (force) x (distance from the pivot) = 1 foot-pound. (B)
Answer:
Ea = 112500[J]
Eb = 87500[J]
Explanation:
To solve this problem we must use the principle of energy conservation which tells us that the energy of a body plus the work done or applied by the body equals the final energy of a body.
This can be easily visualized by the following equation:
Now we must define the energies at points A & B.
<u>For point A</u>
At point A we only have kinetic energy since it moves at 15 [m/s]
So the kinetic energy
![E_{A}=\frac{1}{2}*m*v_{A}^{2} \\E_{A}=\frac{1}{2} *1000*(15)^{2} \\E_{A}=112500[J]](https://tex.z-dn.net/?f=E_%7BA%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av_%7BA%7D%5E%7B2%7D%20%20%5C%5CE_%7BA%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%2A1000%2A%2815%29%5E%7B2%7D%20%5C%5CE_%7BA%7D%3D112500%5BJ%5D)
The final kinetic energy can be calculated as follows:
![112500-25000=E_{B}\\E_{B}=87500[J]](https://tex.z-dn.net/?f=112500-25000%3DE_%7BB%7D%5C%5CE_%7BB%7D%3D87500%5BJ%5D)
