Answer:
The final temperature of both objects is 400 K
Explanation:
The quantity of heat transferred per unit mass is given by;
Q = cΔT
where;
c is the specific heat capacity
ΔT is the change in temperature
The heat transferred by the object A per unit mass is given by;
Q(A) = caΔT
where;
ca is the specific heat capacity of object A
The heat transferred by the object B per unit mass is given by;
Q(B) = cbΔT
where;
cb is the specific heat capacity of object B
The heat lost by object B is equal to heat gained by object A
Q(A) = -Q(B)
But heat capacity of object B is twice that of object A
The final temperature of the two objects is given by
![T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b}](https://tex.z-dn.net/?f=T_2%20%3D%20%5Cfrac%7BC_aT_a%20%2B%20C_bT_b%7D%7BC_a%20%2B%20C_b%7D)
But heat capacity of object B is twice that of object A
![T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b} \\\\T_2 = \frac{C_aT_a + 2C_aT_b}{C_a + 2C_a}\\\\T_2 = \frac{c_a(T_a + 2T_b)}{3C_a} \\\\T_2 = \frac{T_a + 2T_b}{3}\\\\T_2 = \frac{300 + (2*450)}{3}\\\\T_2 = 400 \ K](https://tex.z-dn.net/?f=T_2%20%3D%20%5Cfrac%7BC_aT_a%20%2B%20C_bT_b%7D%7BC_a%20%2B%20C_b%7D%20%5C%5C%5C%5CT_2%20%3D%20%5Cfrac%7BC_aT_a%20%2B%202C_aT_b%7D%7BC_a%20%2B%202C_a%7D%5C%5C%5C%5CT_2%20%3D%20%5Cfrac%7Bc_a%28T_a%20%2B%202T_b%29%7D%7B3C_a%7D%20%5C%5C%5C%5CT_2%20%3D%20%5Cfrac%7BT_a%20%2B%202T_b%7D%7B3%7D%5C%5C%5C%5CT_2%20%3D%20%5Cfrac%7B300%20%2B%20%282%2A450%29%7D%7B3%7D%5C%5C%5C%5CT_2%20%3D%20400%20%5C%20K)
Therefore, the final temperature of both objects is 400 K.
Answer:
(a) 0.3778 eV
(b) Ratio = 0.0278
Explanation:
The Bohr's formula for the calculation of the energy of the electron in nth orbit is:
![E=\frac {-13.6}{n^2}\ eV](https://tex.z-dn.net/?f=E%3D%5Cfrac%20%7B-13.6%7D%7Bn%5E2%7D%5C%20eV)
(a) The energy of the electron in n= 6 excited state is:
![E=\frac {-13.6}{6^2}\ eV](https://tex.z-dn.net/?f=E%3D%5Cfrac%20%7B-13.6%7D%7B6%5E2%7D%5C%20eV)
![E=-0.3778\ eV](https://tex.z-dn.net/?f=E%3D-0.3778%5C%20eV)
Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV
(b) For first orbit energy is:
![E=\frac {-13.6}{1^2}\ eV](https://tex.z-dn.net/?f=E%3D%5Cfrac%20%7B-13.6%7D%7B1%5E2%7D%5C%20eV)
![E=-13.6\ eV](https://tex.z-dn.net/?f=E%3D-13.6%5C%20eV)
![Ratio=\frac {E_6}{E_1}](https://tex.z-dn.net/?f=Ratio%3D%5Cfrac%20%7BE_6%7D%7BE_1%7D)
![Ratio=\frac {-0.3778}{-13.6}](https://tex.z-dn.net/?f=Ratio%3D%5Cfrac%20%7B-0.3778%7D%7B-13.6%7D)
Ratio = 0.0278
I would say Conduction because you are touching the cookie sheet, even though it is hot (so heat) you are physically touching it so it would not be radiation
Density is defined as (mass) per unit (volume). So in order to calculate
the density of a glob of some substance, you pretty much have to measure
its mass and its volume.
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