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WINSTONCH [101]
2 years ago
14

A current in a wire increases from 2 a to 6 a. how will the magnetic field 0.01 m from the wire change? it increases to four tim

es its original value. it increases to three times its original value. it decreases to one-fourth its original value. it decreases to one-third its original value.
Physics
2 answers:
Alisiya [41]2 years ago
6 0

Hi there!

Recall the equation for the magnetic field of a wire (assuming infinite):

B = \frac{\mu _0 i_{encl}}{2\pi r}

B = Magnetic field (T)
μ₀ = Permeability of Free Space (Tm/A)

i = enclosed current (A)
r = distance from wire (m)

From the equation, we can see that there is a DIRECT relationship between the current and the magnetic field.

Therefore, if the current is increased by a factor of 3, <u>the FIELD will also be increased by a factor of three.</u>


kotykmax [81]2 years ago
4 0

Answer:

 It increases to three times it's original value.

Explanation:

B

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<h2>Answer:442758.96N</h2>

Explanation:

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Let P be the pressure at a point.

Let p be the density fluid at a point.

Let v be the velocity of fluid at a point.

Bernoulli's equation states that P+\frac{1}{2}pv^{2}+pgh=constant for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let p_{up} be the pressure of a point just above the wing.

Let p_{do} be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}

So,p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa

Force is given by the product of pressure difference and area.

Given that area is 27ms^{2}.

So,lifting force is 16398.48\times 27=442758.96N

6 0
4 years ago
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Ilia_Sergeevich [38]

Answer:

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3 years ago
find the potential energy of an aircraft weighing 10000 bs at 5000 ft true altitude and 125 kts true air speed
Cloud [144]

Answer:

U=5*10^7ft.Ib

Explanation:

From the question we are told that

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