A current in a wire increases from 2 a to 6 a. how will the magnetic field 0.01 m from the wire change? it increases to four tim
2 answers:
Hi there!
Recall the equation for the magnetic field of a wire (assuming infinite):
B = Magnetic field (T)
μ₀ = Permeability of Free Space (Tm/A)
i = enclosed current (A)
r = distance from wire (m)
From the equation, we can see that there is a DIRECT relationship between the current and the magnetic field.
Therefore, if the current is increased by a factor of 3, <u>the FIELD will also be increased by a factor of three.</u>
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We can solve the problem by using the law of conservation of energy.
When the rocket starts its motion from the Earth surface, its mechanical energy is sum of kinetic energy and gravitational potential energy:
where
m is the rocket's mass
is the rocket initial speed
is the gravitational constant
is the Earth's mass
is the distance of the rocket from the Earth's center (so, it corresponds to the Earth's radius)
The mechanical energy of the rocket when it is very far from the Earth is just kinetic energy (because the gravitational potential at infinite distance from Earth is taken to be zero):
where
is the final speed of the rocket.
By equalizing the initial energy and the final energy, we can find the final velocity:
When the rocket starts its motion from the Earth surface, its mechanical energy is sum of kinetic energy and gravitational potential energy:
where
m is the rocket's mass
The mechanical energy of the rocket when it is very far from the Earth is just kinetic energy (because the gravitational potential at infinite distance from Earth is taken to be zero):
where
By equalizing the initial energy and the final energy, we can find the final velocity:
The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
<h3> Magnetic dipole moment of the bar magnet</h3>
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;
where;
- B is magnetic field
- m is dipole moment
- μ is permeability of free space
m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
Learn more about dipole moment here: brainly.com/question/27590192
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Answer:
(a) 1767.43 N
(b) 182.45 N
Explanation:
Radius of earth, R = 6450 km
Weight of person, W = 7070 N
mass of person, m = W / g = 7070 / 9.8 = 721.4 kg
(a) h = 6450 km
The value of acceleration due to gravity on height is given by
g' = g / 4 = 9.8 / 4 = 2.45 m/s^2
The weight of the person at such height is
W' = m x g' = 721.4 x 2.45
W' = 1767.43 N
(b) h = 33700 km
The value of acceleration due to gravity on height is given by
g' = g x 0.0258 = 9.8 x 0.0258 = 0.253 m/s^2
The weight of the person at such height is
W' = m x g'
W' = 721.4 x 0.253
W' = 182.45 N