the missing force is spring force.
The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position. due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.
the spring force is given as
F = kx
where F = spring force ,k = spring constant , x = stretch in the spring.
the spring force balances the weight of the object in down direction and hence keeps the block from falling down.
Answer:
<h2>64.4 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 9.2 kg
acceleration = 7 m/s²
We have
force = 9.2 × 7 = 64.4
We have the final answer as
<h3>64.4 N</h3>
Hope this helps you
Answer:
C) 64lb
Explanation:
use the linearity method to find the weight of nadir on another planet, it is applied as follows.
Nadir Weight in earth ⇒ Nadir weight in another planet
Vince Weigh in eart ⇒ X
our goal is to find the weight of vince in another planet (X), for this we multiply the diagonal that continents the data and divide among the remaining
140pounds ⇒ 56lb
160pounds ⇒ X
X=
Vince weigh on the other planet is C) 64lb
Answer:
The force of static friction acting on the luggage is, Fₓ = 180.32 N
Explanation:
Given data,
The mass of the luggage, m = 23 kg
You pulled the luggage with a force of, F = 77 N
The coefficient of static friction of luggage and floor, μₓ = 0.8
The formula for static frictional force is,
Fₓ = μₓ · η
Where,
η - normal force acting on the luggage 'mg'
Substituting the values in the above equation,
Fₓ = 0.8 x 23 x 9.8
= 180.32 N
Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N
