KE at 16m/s
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Givens
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m = 575 kg
v = 16 m/s
Formula
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KE = 1/2 m* v^2
KE = 1/2 575 * 16^2
KE = 73600
Second Question
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m = 575
v = 32 m/s
KE = 1/2 mv^2
KE = 1/2 575 * 32^2
KE = 294400
Third Question
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Ke2 = KE1 * k where k is the number of times greater the second is than the first.
294400 = k * 73600
k = 294400 / 73600
k = 4 So the KE of the second condition is 4 times the first.
Answer:
31.8 m in the positive x-direction
Explanation:
Here we have an example of multiplication of a vector by a scalar.
In order to perform this operation, we have to:
- multiply the magnitude of the vector by the scalar
- reverse the direction of the vector if the scalar is a negative number
In this problem, the original vector has a lenght of 8.6 m and it points in the negative x direction. Now we have to find the vector -3.7A, so we have:
- The magnitude is obtained by calculating the product

- The direction is reversed, because the scalar is -3.7, so the new vector will point in the positive x-direction
So the final vector is 31.8 m in the positive x-direction, and therefore its x-component is also 31.8 m in the positive direction.
Answer:
Explanation:
Frequency is oscillations per second.
So we have to find the Number of seconds she paced.
2 minutes = 2 X 60
= 120 seconds
Therefore,
Her frequency = 10 / 120
= 1/12 Hertz
Answer:
Anything in an experiment that remains unchanged.
Explanation:
An example could be the temperature of the laboratory room. If there is something that has an effect on an experiment that is not variable, it is a constant. Another constant could be, say, if you were doing calculations with the same amount and kind of fluid throughout the experiment, then that fluid would also be a constant.