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olasank [31]
3 years ago
5

3. If the potential difference is 120 volts and the resistance is 60 ohms, what is the current?

Physics
1 answer:
Ede4ka [16]3 years ago
8 0

Answer:

2 amperes

Explanation:

According to Ohms law

v = ir

v = voltage

I = current

r = resistance

From the question

v = 120volts

r = 60 ohms

I = ?

Using ohms law ,

v = ir

120 = I x 60

Divide both sides by 60

120/60 = I x 60/60

2 = I

I = 2 amperes

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stepan [7]

Answer:

absorb more heat and get heated quickly

Explanation:

7 0
3 years ago
Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a
cupoosta [38]

Answer:

2.2 s

Explanation:

Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point =  mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)

So, T = 2π√(I/mgh)

T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

T = 2π√(3.66 m/(29.4 m/s² ))

T = 2π√(0.1245 s² ))

T = 2π(0.353 s)

T = 2.22 s

T ≅ 2.2 s

So, the period of the man's leg is 2.2 s

7 0
3 years ago
While riding a skateboard, Nina ran into a rough patch of pavement, but she thought she could ride right over it. Instead, the s
Jet001 [13]

Answer:

inertia

Explanation:

While riding a skateboard, Nina ran into a rough patch of pavement, but she thought she could ride right over it. Instead, the skateboard stopped but Nina didn't. Her (Blank) kept her moving forward, so she fell off the skateboard.inertia

3 0
3 years ago
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ladessa [460]

Answer:

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Using the equation of motion

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Substituting u for 6 m/s, t for 3 s, a for 1.4 m/s2 we obtain

S=6*3+(0.5*1.4*3^{2}=18+6.3=24.3 m


7 0
3 years ago
Juan inflates a balloon and then releases its end to let the balloon go free as air comes out. The balloon then flies around the
sergeinik [125]

action and reaction forces

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