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2 years ago

Consider a situation where the acceleration of an object is always directed perpendicular to its velocity. This means that

Physics

1 answer:

Bond [772]2 years ago

7 0

Answer:

this situation would not be physically possible

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An automatic dryer spins wet clothes at an angular speed of 5.2 rad/s. Starting from rest, the dryer reaches its operating speed

Dvinal [7]

<h2>Time taken by dryer to come up to speed is 1.625 seconds.</h2>

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 0 rad/s

Final velocity, v = 5.2 rad/s

Time, t = ?

Acceleration, a = 3.2 rad/s²

Substituting

v = u + at

5.2 = 0 + 3.2 x t

t = 1.625 s

Time taken by dryer to come up to speed is 1.625 seconds.

6 0

3 years ago

HELPPP WILL GIVE BRAINLIEST!!!

lesantik [10]

Answer: C

Explanation: As the universe stretches it expands more and more the distance between each other. Hope this helps.

5 0

2 years ago

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Which formula can be used to find the x-component of the resultant vector?

lora16 [44]

The resulting vector is the sum of the T + U + V vectors component to component. Therefore, if you want to find the x component of the resulting vector, the correct formula is:

Tx + Ux + Vx

3 0

2 years ago

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Identify the characteristics of protists. Check all that apply.

romanna [79]

Answer:

There are no examples

Explanation:

3 1

2 years ago

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The 630-nm light from a helium-neon laser irradiates a grating. The light then falls on a screen where the first bright spot is

dimaraw [331]

Answer:

464.8 nm

Explanation:

The second wavelength of light can be calculated using the next equation:

$\lambda = \frac{x*d}{L}$

Where:

λ : is the wavelength of light

x: is the distance from the central maximum

d: is the distance between the spots

L: is the lenght from the screen to the bright spot

For the first wavelength of light we have:

$\lambda_{1} = \frac{x_{1}*d}{L}$

$630 \cdot 10^{-9} m = \frac{0.61 m*d}{L}$

$\frac{d}{L} = \frac{630 \cdot 10^{-9} m}{0.61 m} = 1.033 \cdot 10^{-6}$ (1)

For the second wavelength of light we have:

$\lambda_{2} = \frac{x_{2}*d}{L}$

$\lambda_{2} = 0.45 m*\frac{d}{L}$ (2)

By entering equation (1) into equation (2) we have:

$\lambda_{2} = 0.45 m* 1.033 \cdot 10^{-6} = 4.648 \cdot 10^{-7} m = 464.8 nm$

Therefore, the second wavelength is 464.8 nm

I hope it helps you!

3 0

2 years ago