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disa [49]
3 years ago
12

Consider a situation where the acceleration of an object is always directed perpendicular to its velocity. This means that

Physics
1 answer:
Bond [772]3 years ago
7 0

Answer:

this situation would not be physically possible

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A 33.0-kg child starting from rest slides down a water slide with a vertical height of 15.0 m. (Neglect friction.)
Temka [501]

This question involves the concept of the conservation of energy.

(a) The child's speed halfway will be "12.13 m/s".

(b) The child's speed three-fourth way will be "14.86 m/s".

(a)

Using the <em>law of conservation of energy</em>:

Potential Energy Lost = Kinetic Energy Gained

mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = halfway = height/2 = 15 m/2 = 7.5 m

Therefore,

v = \sqrt{(2)(9.81\ m/s^2)(7.5\ m)}

<u>v = 12.13 m/s</u>

<u />

(b)

Using the <em>law of conservation of energy</em>:

Potential Energy Lost = Kinetic Energy Gained

mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = three-fourth way down = \frac{3}{4}height = \frac{3}{4}(15\ m) = 11.25\ m

Therefore,

v = \sqrt{(2)(9.81\ m/s^2)(11.25\ m)}

<u>v = 14.86 m/s</u>

<u />

Learn more about the <em>law of conservation</em> of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture shows the <em>law of conservation of energy</em>.

7 0
3 years ago
Part A
Gemiola [76]

The Mass of the barter and the ball is 3.1kg

Data Given;

  • F = 1.1*10^-9N
  • r = 0.76m
  • G = 6.67*10^-11 m^3 kg^-1 s^-1

Assuming the barter and the ball have equal mass, we can apply gravitational force formula.

<h3>Gravitational Force</h3>

F = \frac{Gm_1m_2}{r^2}

This is product of the mass of the two bodies and divided by the square of their distance apart.

Substituting the values into the formula

F = \frac{Gm_1m_2}{r^2\\}\\m_1 = m_2 = m\\1.1*10^-^9=\frac{6.67*10^-^1^1*m^2}{0.76^2}  \\m^2 = \frac{1.1*10^-^9*0.76^2}{6.67*10^-^1^1} \\m^2 = 9.525\\m = \sqrt{9.525}\\m =3.086=3.1kg

From the calculations above, the mass of the barter and the ball is 3.1kg

Learn more on gravitational force here;

brainly.com/question/11359658

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3 years ago
Would you choose to have your genome sequenced to screen for diseases
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Choose all of the items that are incorrectly matched. A) inactivation gate — closed at restB) activation gate — open at restC) i
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