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irina1246 [14]
4 years ago
12

The dependent variable (DV) changes while the independent variable (IV) does not. False or True

Physics
2 answers:
miv72 [106K]4 years ago
5 0

Answer:true

Explanation:

Solnce55 [7]4 years ago
4 0

Answer: False

Explanation: An easy way to think of independent and dependent variables is, when you're conducting an experiment, the independent variable is what you change, and the dependent variable is what changes because of that.

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You are standing in an elevator that is accelerating upward at 1m/s². Which of the following pairs of forces is an action-reacti
Lostsunrise [7]

Answer:

B The force that the floor of the elevator exerts on you and the force that you exert on the floor of the elevator

Explanation:

A. is incorrect because the force of gravity on you will always stays the same while the force of the elevator exerts on you changes as it takes you upward

B. is correct in accordance to Newton's 3rd law of action and reaction forces.

C. is incorrect because gravity force stays the same while the force that you exerts on the floor change as elevator moving upward.

D. is incorrect although it states Newton's 1st law. However there can still be pair of forces (part B) that could counter balance each other among other forces.

5 0
3 years ago
If a car moves with a uniform speed of 2m/s in a circle of radius 0.4m, what is its angular speed?
REY [17]

Answer:

The car's angular speed is \frac{rad}{s}.

Explanation:

Angular velocity is usually measured with \frac{radians}{sec}, so I'm going to use that to answer your question.

The relationship between tangential velocity and angular velocity (ω)  is given by:

V = \omega R

Using the values from the question, we get:

2 \frac{m}{s} = \omega (0.4m)

\omega = 5 \frac{rad}{s}

Therefore, the car's angular speed is 5 \frac{rad}{s}.

Hope this helped!

3 0
3 years ago
A sled with a mass of 20 kg slides along frictionless ice at 4.5 m/s. It then crosses a rough patch of snow that exerts a fricti
Ugo [173]

Use Newton's second law to determine the acceleration being applied to the sled. There are three forces at work on the sled (its weight, the force normal to the ground, and friction) but two of them cancel, leaving friction as the only effective force. This vector is pointed in the opposite direction of the sled's movement, so if we take the direction of its movement to be the positive axis, we would find the acceleration due to the friction to be

\vec F_G+\vec F_N+\vec F_F=m\vec a\iff-12\,\mathrm N=(20\,\mathrm{kg})a\implies a=-0.6\,\dfrac{\rm m}{\mathrm s^2}

Now we use the formula

{v_f}^2-{v_i}^2=2a(x_f-x_i)

to find the distance it travels. The sled comes to a rest, so v_f=0, and let's take the starting position x_i=0 to be the origin. Then the distance traveled x_f-x_i=x_f is

-\left(4.5\,\dfrac{\rm m}{\rm s}\right)^2=2\left(-0.6\,\dfrac{\rm m}{\mathrm s^2}\right)x_f\implies x_f\approx17\,\mathrm m

6 0
3 years ago
You move a 4 N object 10 meters. Find work
Trava [24]

Answer: 40 J

Explanation: Work is equal to the product of force and distance.

W = Fd

= 4N ( 10 m)

= 40 J

8 0
4 years ago
What are some characteristics of an Effective Early Childhood teacher ​
nata0808 [166]

Answer:

Enthusiasm, patience, and the respect of differences.

Explanation:

It takes courage and time for an effective early childhood teacher to understand and appreciate what she has with the kids and to understand them and help kids with creativity and to make them feel awesome.

6 0
3 years ago
Read 2 more answers
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