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2 years ago

Makala arrives late to class and misses the first few minutes of the lecture. These are the notes she takes:

Physics

2 answers:

Nadya [2.5K]2 years ago

8 0

Answer:

B. Quantum Mechanics

Explanation:

Edge 2021

lukranit [14]2 years ago

4 0

Answer:

B. Quantum Mechanics

Explanation:

Quantum mechanics is the foundation of all quantum physics including quantum chemistry, quantum field theory, and quantum information science.

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The law of conservation of energy states that

IgorLugansk [536]

Energy is neither created nor destroyed

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3 years ago

What would an american flag look like if you viewed it through a filter that transmits only red light? what would it look like t

chubhunter [2.5K]

Red: The red parts will stay the same
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3 years ago

Read 2 more answers

What is the net force required to accelerate a 16 kg box at a rate or 1.4 m/s^2

stich3 [128]

You can use Newton's Second Law which states:
$\sum \vec{F} = m\vec{a}$

Plug in given information:
$\sum \vec{F}=16(1.4) = 22.4N$

This is closest to option b which is your answer.

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2 years ago

Who speaks the line "Lord, what fools these mortals be"?

ivanzaharov [21]

The answer is D.Puck.

♡♡Hope I helped!!! :)♡♡

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2 years ago

A skier is pulled by a towrope up a frictionless ski slope that makes an angle of 12 degrees with the horizontal. The rope moves

MArishka [77]

Answer:

Explanation:

Given,

Work done by the rope 900 m/s.
Angle of inclination of the slope = $\theta\ =\ 12^o$
Initial speed of the skier = v = 1.0 m/s
Length of the inclined surface = d = 8.0 m

part (a)

The rope is doing the work against the gravity on the skier to uplift up to the inclined surface. Therefore the work done by the rope is equal to the work done on the skier due to the gravity

$\therefore W_r\ =\ W_g\ =\ 900\ J$

In both cases the height attained by the skier is equal. and the work done by gravity does not depend upon the speed of the skier.

part (b)

Initial speed of the skier = v = 1.0 m/s.

Rate of the work done by the rope is power of the rope.

$Power\ =\ \dfrac{\Delta W}{\Delta t}\\\Rightarrow P\ =\ \dfrac{\Delta W}{\dfrac{d}{v}}\\\Rightarrow P\ =\ \dfrac{\Delta W\times v}{d}\\\Rightarrow P\ =\ \dfrac{900\times 1.0}{8.0}\\\Rightarrow P\ =\ 112.5\ Watt$

Part (c)

Initial speed of the skier = v = 2.0 m/s.

Rate of the work done by the rope is power of the rope.

4 0

2 years ago