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Dima020 [189]
3 years ago
10

If a car moves with a uniform speed of 2m/s in a circle of radius 0.4m, what is its angular speed?

Physics
1 answer:
REY [17]3 years ago
3 0

Answer:

The car's angular speed is \frac{rad}{s}.

Explanation:

Angular velocity is usually measured with \frac{radians}{sec}, so I'm going to use that to answer your question.

The relationship between tangential velocity and angular velocity (ω)  is given by:

V = \omega R

Using the values from the question, we get:

2 \frac{m}{s} = \omega (0.4m)

\omega = 5 \frac{rad}{s}

Therefore, the car's angular speed is 5 \frac{rad}{s}.

Hope this helped!

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a bowling ball has a mass of 6 kilograms. a tennis ball has a mass of 0.06 kilogram. how much inertia does the bowling ball have
Andreyy89

Answer:

100 times

Explanation:

Since inertia is directly proportional to the mass of an object, the higher the mass the higher the inertia. In this case, 6 Kg is 100 times heavier than 0.06 Kg to imply The bowling ball  has 100 times more inertia than the tennis  ball because it has 100 times more mass

5 0
3 years ago
A teacher wants to perform a classroom demonstration that illustrates both chemical and physical changes. Which would be the bes
anygoal [31]

Answer

D) burning a candle

Explanation

When burning a candle no new substance is form.

We have both physical and chemical change occuring.

Physical part: Melting of the solid wax and evaporation of the liquid forms the physical change.

Chemical part: burning of the wax vapour forms the chemical change.

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3 years ago
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If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the 1200.-kg pick-up truck behind him continues tr
Alborosie

Answer: 20.2 m/s

Explanation:

From the question above, we have the following data;

M1 = 800kg

M2 = 1200kg

V1 = 13m/s

V2 = 25m/s

U (common velocity) =?

M1V1 + M2V2 = (M1 + M2). U

(800*13) + (1200*25) = (800+1200) * U

10400 + 30000 = 2000u

40400 = 2000u

U = 40400 / 2000

U = 20.2 m/s

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A 1.2-kg mass is projected from ground level with a velocity of 30 m/s at some unknown angle above the horizontal. A short time
Dmitriy789 [7]

Answer:

K_f = 351.84 J

Explanation:

Using the conservation of energy K:

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so:

\frac{1}{2}mv^2 = K_f + mgh

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Then, replacing values, we get:

\frac{1}{2}(1.2kg)(30m/s)^2 = K_f + (1.2kg)(9.8m/s^2)(16m)

solving for K_f:

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How elements are arranged in the groups of periodic table
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