Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
F(x) = x(2 - x)
g(x) = 3x
Substitute 3x for x in the function f(x)
h(x) = f(x) <span>∘ g(x) = f(g(x)) = 3x(2 - 3x)
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What is the mean, median, mode, and range of this data set, 2,3,2,4,3,3,3,4,2,3,4,2,4,4,9,3,4,4
slava [35]
Answer:
Mean: 3.5
Median: 3
Mode: 4
Range: 7
Step-by-step explanation:
Answer: 4=-2x -1 and y=-1 2x
Balance in account cannot be less than
