Answer : 13.64 mL
Explanation : The reaction requires 13.64 mL of NaOH
From the reaction we know that oxalic acid requires two moles of NaOH so we have to calculate the number of moles of both.
0.150 L X 0.1500 moles/L = 2.25 X
So the moles of NaOH will be 2 X (2.25 X ) = 4.5 X
Now, we know the concentration of NaOH as 0.330 M
4.5 X moles / 0.330 moles/L = 0.01364 L or 13.64 mL
So, the volume of NaOH needed to neutralize oxalic acid will be 13.64 mL
By the following statement above, milk is an example of : c. colloid
Milk is an emulsified colloid of liquid butterfat globules dispersed within a water-based solution.
colloid is ultra microscopic particles of one substance dispersed through a second substance.
hope this help
Answer:
Explanation:
We are asked to find the pressure of a gas given a change in volume. Since the temperature remains constant, we are only concerned with volume and pressure. We will use Boyle's Law, which states the volume is inversely proportional to the pressure. The formula for this law is:
Initially, the oxygen gas occupies a volume of 18.7 liters at a pressure of 1.19 atmospheres.
The gas expands to a volume of 29.4 liters, but the pressure is unknown.
We are solving for the new pressure, so we must isolate the variable . It is being multiplied by 29.4 liters. The inverse operation of multiplication is division. Divide both sides of the equation by 29.4 L.
The units of liters cancel.
The original measurements all have 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 9 in the ten-thousandth place to the right of this place tells us to round the 6 up to a 7.
The pressure of the gas sample is approximately <u>0.757 atmospheres.</u>