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SIZIF [17.4K]
3 years ago
14

How many grams of Na2SO4 are required to make 0.30 L of 0.500 M Na2SO4?

Chemistry
1 answer:
RSB [31]3 years ago
3 0

Answer: 21.3 g of Na_2SO_4 are required to make 0.30 L of 0.500 M Na_2SO_4.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of Na_2SO_4 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{142g/mol}

Now put all the given values in the formula of molality, we get

0.500M=\frac{xg}{142g/mol\times 0.30L}

x=21.3g

Therefore, 21.3 g of Na_2SO_4 are required to make 0.30 L of 0.500 M Na_2SO_4.

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