The value of Kc for the equilibrium is 0.150 mole² / litre ²
<u>Explanation:</u>
<u>Given:</u>
An equilibrium mixture in an 1.00 L vessel contains 5.30 moles of
Mg(OH )₂ 0.800 moles of Mg²⁺ and 0.0010 moles OH₋
We have to find the value of Kc
- Step 1: Find the equilibrium Concentration.
- Step 2: Substitute the values in the equation.
- Step 3: Find the value of Kc.
- I have attached the document for the detailed explanation
The value of Kc for the equilibrium is 0.150 mole² / litre ²
true, in a stronger gravitational field the weight will be larger.
Answer:
Color change, precipitation, bubbling
Explanation:
Chemical change changes the chemical composition and undergoes a process in which it results as a new substance.
Answer:
Detail is given below.
Explanation:
Chemical equation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
This reaction shows that when ammonia react with oxygen it form water and nitrogen gas.
There are two reactants on left hand side oxygen and ammonia. Ammonia is formed when nitrogen and hydrogen react. While on right hand side there are two products nitrogen and water. Water is formed by the reaction of hydrogen and oxygen.
The given reaction also shows that it follow the law of conservation of mass.
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.