<u>Answer:</u> The volume when the pressure and temperature has changed is ![1.6\times 10^2mL](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E2mL)
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
Let us assume:
![P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K](https://tex.z-dn.net/?f=P_1%3D1.20atm%5C%5CV_1%3D795mL%5C%5CT_1%3D116%5EoC%3D%5B116%2B273%5DK%3D389K%5C%5CP_2%3D0.55atm%5C%5CV_2%3D%3FmL%5C%5CT_2%3D75%5EoC%3D%5B75%2B273%5DK%3D348K)
Putting values in above equation, we get:
![\frac{1.20atm\times 795mL}{389K}=\frac{0.55atm\times V_2}{348K}\\\\V_2=\frac{1.20\times 795\times 348}{0.55\times 389}=1.6\times 10^3mL](https://tex.z-dn.net/?f=%5Cfrac%7B1.20atm%5Ctimes%20795mL%7D%7B389K%7D%3D%5Cfrac%7B0.55atm%5Ctimes%20V_2%7D%7B348K%7D%5C%5C%5C%5CV_2%3D%5Cfrac%7B1.20%5Ctimes%20795%5Ctimes%20348%7D%7B0.55%5Ctimes%20389%7D%3D1.6%5Ctimes%2010%5E3mL)
Hence, the volume when the pressure and temperature has changed is ![1.6\times 10^2mL](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E2mL)
B trench
Explanation:
The feature found at most convergent margins is a trench.
A trench is a large depression that typifies most convergent margins.
- Oceanic trenches are natural topographic depressions found on the sea floor.
- These depressions forms where two plate boundaries converges.
- The denser one slides beneath the less dense one into the asthenosphere below.
- This is called a subduction zone.
- The margin between the two plates that are depression is a trench.
learn more:
Lithosphere brainly.com/question/2998243
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One thing about mercury is that Mercury is the smallestplanet in the Solar System.
Answer:
Explanation:
use gas law eqation
P1 * V1 / T1 = P2 * V2 /T2
600*V1/227 = 300*800/23
V1 = 300*800*227 / 23*600 = ............ can you solve this and get the answer?
The answer is a. H+ and H2O. For a half-reaction in acidic solutions, elements that are not hydrogen and oxygen are balanced first. Then we add H2O to balance oxygen atoms and we add H+ to balance the hydrogen atoms. We do the same steps for basic solutions, but we also add hydroxide ions OH- in the latter part.