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Dovator [93]
3 years ago
14

A uniform thin rod of mass M = 3.11 kg M=3.11 kg pivots about an axis through its center and perpendicular to its length. Two sm

all bodies, each of mass m = 0.213 kg m=0.213 kg , are attached to the ends of the rod. What must the length L L of the rod be so that the moment of inertia of the three-body system with respect to the described axis is I = 0.831 kg ⋅ m 2 I=0.831 kg·m2 ?
Physics
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

L=1.49 m

Explanation:

We are given that

M=3.11 kg

m_1=m_2=0.213 kg

I=0.831 kgm^2

We have to find the length L of the rod

Moment of inertia of the system

I=\frac{ML^2}{12}+\frac{mL^2}{4}+\frac{mL^2}{4}

0.831=L^2(\frac{M}{12}+\frac{2m}{4})=L^2(\frac{3.11}{12}+\frac{0.213}{2})

(\frac{3.11+1.278}{12}L^2=0.831

L^2=\frac{0.813\times 12}{3.11+1.278}

L=\sqrt{\frac{0.813\times 12}{3.11+1.278}}

L=1.49 m

Hence, the length of rod=L=1.49 m

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\\ \rm\rightarrowtail W=mgh

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\\ \rm\rightarrowtail h=49.1m

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How do I solve this​
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Answer:

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Explanation:

To solve this problem we need to know the electron is a subatomic particle with a negative elementary electrical charge (-1,602 × 10-19 C), The expression to calculate the work is given by:

W = q*V

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3 years ago
An electron of mass 9.11 x 10^-31 kg has an initial speed of 4.00 x 10^5 m/s. It travels in a straight line, and its speed incre
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Answer:

a.     F = 2.32*10^-18 N

b.     The force F is 2.59*10^11 times the weight of the electron

Explanation:

a. In order to calculate the magnitude of the force exerted on the electron you first calculate the acceleration of the electron, by using the following formula:

v^2=v_o^2+2ax         (1)

v: final speed of the electron = 6.60*10^5 m/s

vo: initial speed of the electron = 4.00*10^5 m/s

a: acceleration of the electron = ?

x: distance traveled by the electron = 5.40cm = 0.054m

you solve the equation (2) for a and replace the values of the parameters:

a=\frac{v^2-v_o^2}{2x}=\frac{(6.60*10^5m/s)^2-(4.00*10^5m/s)^2}{2(0.054m)}\\\\a=2.55*10^{12}\frac{m}{s^2}

Next, you use the second Newton law to calculate the force:

F=ma

m: mass of the electron = 9.11*10^-31kg

F=(9.11*10^{-31}kg)(2.55*10^{12}m/s^2)=2.32*10^{-18}N

The magnitude of the force exerted on the electron is 2.32*10^-18 N

b. The weight of the electron is given by:

F_g=mg=(9.11*10^{-31}kg)(9.8m/s^2)=8.92*10^{-30}N

The quotient between the weight of the electron and the force F is:

\frac{F}{F_g}=\frac{2.32*10^{-18}N}{8.92*10^{-30}N}=2.59*10^{11}

The force F is 2.59*10^11 times the weight of the electron

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In social learning theory, it's a process where people tend to observe the actions of others and then imitate them.

Now, since this father wants to teach his son to start helping his mother do the do laundry, what he can do according to social learning theory is to help with the laundry himself first.

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vector with direction equal to the axis X.

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E_{total}=E_1+E_2

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3 years ago
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