Answer:The velocity of the object will be 5m/s or 13.23m/s
Explanation:
force exerted by the object= 30N
distance displayed by the object by the action of force=6.0m
mass of object=10kg
velocity gained by the object=?
Answer:
2.84 seconds
Explanation:
t = ?
distance = 125
Velocity origianal = 60 m/hr = 88 ft/s
AVERAGE velocity = 88/2 = 44 ft/s
44 t = 125
t = 125/44 = 2.84 s
Answer:
The ball travels a distance of 20 m in the time interval of 4 s
Explanation:
Using s = ut + 1/2at² where s = distance travelled by the ball, u = initial velocity of ball = 0 m/s (since it starts from rest), a = acceleration of the ball = 2.50 m/s² and t = time = 4 s.
Substituting the variables into the equation, we have
s = ut + 1/2at²
s = 0 × 4 s + 1/2 × 2.50 m/s² × (4 s)²
s = 0 + 1/2 × 2.50 m/s² × 16 s²
s = 1/2 × 40 m
s = 20 m
So, the ball travels a distance of 20 m in the time interval of 4 s.
i. 1,350 calories
j. 992 calories
k. 235.6 calories
2. Calories of energy into water = (amount of water, in grams) x (change in the water's temperature, in °C)
3.a. 840 calories
3.b. 840 calories
4. 80°C