Answer:
the net work is 0
Explanation:
in an isolated system, there is no energy entering or exiting the system, and since work is dependent on the change in energy (W = ΔE) , with no change in energy, there is no work done. the net work done on or by the system must be 0
Explanation:
Power output of the bulb:
0.021 × 60 W = 1.26 W
Energy produced by the bulb in 1 second:
E = Pt
E = (1.26 W) (1 s)
E = 1.26 J
Round as needed.
Hertz Pitch and frequency
Radioactive decay is given by:
N = No x e^(-λt)
We know that N/No has to be 0.05
λ = 0.15
0.05 = e^(-0.15t)
t = ln(0.05)/(-0.15)
t = 19.97 days
