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3 years ago

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A photon has momentum of magnitude 8.30×10−28 kg⋅m/s . Part APart complete What is the energy of this photon? Give your answer i

n joules. E = 2.49×10−19 J SubmitPrevious Answers Correct Part BPart complete What is the energy of this photon? Give your answer in electron volts. E = 1.55 eV SubmitPrevious Answers Correct Part C What is the wavelength of this photon?

1 answer:

d1i1m1o1n [39]3 years ago

6 0

Answer with Explanation:

We are given that

Momentum of photon= $8.3\times 10^{-28} kg.m/s$

a. We have to find the energy of this photon.

Speed of photon= $c=3\times 10^8 m/s$

We know that

Momentum=p= $\frac{h}{\lambda}$

Where

h= $6.63\times 10^{-34}$ J-s=Plank's constant

$\lambda=$ Wavelength of photon

$\lambda=\frac{h}{p}$

$\lambda=\frac{6.63\times 10^{-34}}{8.3\times 10^{-28}}$

$\lambda=7.99\times 10^{-7}$ m

$E=\frac{hc}{\lambda}$

$E=\frac{6.63\times 10^{-34}\times 3\times 10^8}{7.99\times 10^{-7}}$

$E=2.49\times 10^{-19}$ J

Hence, the energy of photon= $2.49\times 10^{-19}$ J

B.Energy of photon in electron volt= $\frac{2.49\times 10^{-19}}{1.6\times 10^{-19}}=1.55 eV$

Energy of photon= $1.55eV$

C.Wavelength of photon = $\lambda=7.99\times 10^{-7}m$

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Answer:

a) v = 31.67 cm / s , b) v = -29.36 cm / s , c) v= 29.36 cm/s, d) x = 3.46 cm

Explanation:

The angular velocity in a simple harmonic movement is

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w = √ 23.2 / 0.37

w = 7,918 rad / s

a) the expression against the movement is

x = A cos (wt + Ф)

Speed is

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The maximum speed occurs for cos = ± 1

v = A w

v = 4.0 7,918

v = 31.67 cm / s

b) as the object is released from rest

0 = -A w sin (0+ Фi)

sin Ф = 0

Ф = 0

The equation is

x = 4.0 cos (7,918 t)

v = -4.0 7,918 sin (7,918 t)

v = - 31.67 sin (7.918t)

Let's look for the time for a displacement of x = 1.5 cm, remember that the angles must be in radians

7,918 t = cos⁻¹ 1.5 / 4.0

t = 1,186 / 7,918

t = 0.1498 s

We look for speed

v = -31.67 sin (7,918 0.1498)

v = -29.36 cm / s

c) if the object passes the equilibrium equilibrium position again at this point the velocity has the same module, but the opposite sign

v = 29.36 cm / s

d) let's look for the time for the condition v = v_max / 2

31.67 / 2 = 31.67 sin ( 7,918 t)

7.918t = sin⁻¹ 0.5

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Answer:

Option C and D only

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Option A is incorrect because refractive index of a material is the ratio of speed of light in vacuum to the speed of light in a any given medium

Option B is correct as the speed of light in vacuum is always greater than the speed of light in any given medium.

Option C is correct

Option D is incorrect

Option E is incorrect because the denser the medium the more is the refractive index. Water is denser than air, hence it should have more refractive index as compared to that of air.

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2 years ago

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The best and most correct answer among the choices provided by your question is the second choice or letter B.

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2 years ago

To construct a solenoid, you wrap insulated wire uniformly around a plastic tube 7.1 cm in diameter and 57 cm in length. You wou

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Answer:

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The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s. (a) What

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Complete Question

The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s.

(a) What is its angular acceleration in revolutions per minute-squared

(b) How many revolutions does the engine make during this 20 s interval?

rev

Answer:

a

$\alpha = 6261 \ rev/minutes^2$

b

$\theta = 613 \ revolutions$

Explanation:

From the question we are told that

The initial angular speed is $w_i = 1120 \ rev/minutes$

The angular speed after $t = 13.8 s = \frac{13.8}{60 } = 0.23 \ minutes$ is $w_f = 2560 \ rev/minutes$

The time for revolution considered is $t_r = 20 \ s = \frac{20}{60} = 0.333 \ minutes$

Generally the angular acceleration is mathematically represented as

$\alpha = \frac{w_f - w_i }{t}$

=> $\alpha = \frac{2560 - 1120 }{0.23}$

=> $\alpha = 6261 \ rev/minutes^2$

Generally the number of revolution made is $t_r = 20 \ s = \frac{20}{60} = 0.333 \ minutes$ is mathematically represented as

$\theta = \frac{1}{2} * (w_i + w_f)* t$

=> $\theta = \frac{1}{2} * (1120+ 2560 )* 0.333$

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