Question

A photon has momentum of magnitude 8.30×10−28 kg⋅m/s . Part APart complete What is the energy of this photon? Give your answer in joules. E = 2.49×10−19 J SubmitPrevious Answers Correct Part BPart complete What is the energy of this photon? Give your answer in electron volts. E = 1.55 eV SubmitPrevious Answers Correct Part C What is the wavelength of this photon?

Answer 1

Answer with Explanation:

We are given that

Momentum of photon=$8.3\times 10^{-28} kg.m/s$

a. We have to find the energy of this photon.

Speed of photon=$c=3\times 10^8 m/s$

We know that

Momentum=p=$\frac{h}{\lambda}$

Where

h=$6.63\times 10^{-34}$J-s=Plank's constant

$\lambda=$Wavelength of photon

$\lambda=\frac{h}{p}$

$\lambda=\frac{6.63\times 10^{-34}}{8.3\times 10^{-28}}$

$\lambda=7.99\times 10^{-7}$ m

$E=\frac{hc}{\lambda}$

$E=\frac{6.63\times 10^{-34}\times 3\times 10^8}{7.99\times 10^{-7}}$

$E=2.49\times 10^{-19}$ J

Hence, the energy of photon=$2.49\times 10^{-19}$ J

B.Energy of photon in electron volt=$\frac{2.49\times 10^{-19}}{1.6\times 10^{-19}}=1.55 eV$

Energy of photon=$1.55eV$

C.Wavelength of photon =$\lambda=7.99\times 10^{-7}m$