That's impossible. Are you factoring?
Answer:
y = -2
Step-by-step explanation:
This one is easy. As you may know, a axis of symmetry is the line where everything is the same on both sides of it. For this, you can use trial and error or just look at the points on either side. For y = -1, that will put the line in an awkward spot, crossing through 2 slanted lines instead of corners. For x = -1, this just cuts through the shape straight up and down and does not make the shape look equal on both sides of the line at all. Same goes for x = -2. I should probably mention, when you see a line that is described as "x = 1", it is a vertical line, because the line is constantly staying on the point x = 1, while having an infinite number of y-values. When you see "y = 1", it will be horizontal for the same reason, just flipped.
Answer:
![x1](https://tex.z-dn.net/?f=x%3C-5%5Ctext%7B%20or%20%7D%20x%3E1)
Step-by-step explanation:
We have:
![(x+5)(x-1)](https://tex.z-dn.net/?f=%28x%2B5%29%28x-1%29)
And we want to find the value of x such that the expression is positive. So, we can write this as the following inequality:
![(x+5)(x-1)>0](https://tex.z-dn.net/?f=%28x%2B5%29%28x-1%29%3E0)
Solve for the inequality. First, we can solve for the zeros like a normal quadratic. So, pretend the inequality is with an equal sign:
![(x+5)(x-1)=0](https://tex.z-dn.net/?f=%28x%2B5%29%28x-1%29%3D0)
Zero Product Property:
![x+5=0\text{ or } x-1=0](https://tex.z-dn.net/?f=x%2B5%3D0%5Ctext%7B%20or%20%7D%20x-1%3D0)
On the left, subtract 5.
On the right, add 1.
So, our zeros are:
![x=-5, 1](https://tex.z-dn.net/?f=x%3D-5%2C%201)
Since our inequality is a <em>greater than</em>, our answer is an "or" inequality with our answer being all the values to the <em>left</em> of our lesser zero and all the values to the <em>right </em>of our greater zero.
So, our solution is:
![x1](https://tex.z-dn.net/?f=x%3C-5%5Ctext%7B%20or%20%7D%20x%3E1)
And we're done!
Answer:
lateral surface area = 48 inches²
Step-by-step explanation:
The picture below is the square base pyramid you are referring. The lateral area is adding the area of the 4 triangles in the pyramid.
area of a triangle = 1/2 × b × h
The slant height of the triangle is gotten using Pythagoras theorem
lateral surface area = 4 × (1/2 × 3 × 8)
lateral surface area = 4 × 24/2
lateral surface area = 4 × 12
lateral surface area = 48 inches²
Answer: D
Step-by-step explanation:
d should represent the graph