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Thepotemich [5.8K]
3 years ago
6

The diagram shows a person using a piece of gym equipment to lift weights.

Physics
2 answers:
Pachacha [2.7K]3 years ago
7 0

Answer:b the lower leg are inclined planes

Explanation:

Cause I got it right

zysi [14]3 years ago
5 0

Answer:

the answer is c

Explanation:

i got it right

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1. How many seconds in 1 year?
Nezavi [6.7K]

Answer:

3.154e+7

Explanation:

8 0
3 years ago
Read 2 more answers
Movement of a molecule against its concentration gradient can occur through Select one or more: a. facilitated diffusion b. pass
uranmaximum [27]

Answer:

The answer to your question is:

Explanation:

There are two kinds of cell transport passive transportation and active transportation.

Passive transportation does not need energy because molecules move from higher concentration to lower concentration.

Active transportation needs energy because molecules moves against concentration.  

a. facilitated diffusion It's an example of passive transportation so this answer is wrong.

b. passive transport Molecules move in favor of concentration so this answer is wrong.

c. osmosis is another example of passive transport so this answer is wrong.

d. simple diffusion it's another example of passive transport, so it's wrong this answer.

e. active transport this is the right answer.

5 0
3 years ago
The seafloor spreading process at ridges produces what kind of faults?
irga5000 [103]
Active transform faults are between two tectonic<span> structures or faults.</span>
4 0
3 years ago
What is the magnitude momentum of a 2 kg body that moves with a speed of 3 m/s? (1 point)
Naya [18.7K]

Answer:

<h2>D</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 2 kg

velocity/speed = 3 m/s

We have

momentum = 2 × 3 = 6

We have the final answer as

<h3>6 kg.m/s</h3>

Hope this helps you

7 0
3 years ago
La tension que se transmite en la cuerda BD es de 75 lb. Calcula el momento de fuerza generada por la cuerda respecto al punto C
Bas_tet [7]

Answer:

Mc = 1920[lb*in]

Explanation:

Para poder solucionar este problema debemos realizar un análisis estático, por tal motivo lo primero es realizar un diagrama de cuerpo libre con las respectivas fuerzas actuando sobre la barra ABC. DE igual manera calcular la geometría de la configuración mostrada.

El diagrama de cuerpo libre se puede ver en la imagen adjunta, con la solución de este problema.

Lo primero es determinar el angulo t, el cual por medio de las propiedades del triangulo rectángulo se puede determinar.

Con este angulo (t) ya determinado, fijamos la atención en el triangulo BCD, este triangulo no es rectángulo, pero por medio de la ley de senos podemos determinar el angulo omega.

Después de determinar el angulo omega, restamos el angulo (t) para poder determinar el angulo (a).

Seguidamente realizamos una sumatoria de momentos alrededor del punto C, utilizado las respectivas fuerzas con los ángulos descompuestos.

El momento en el punto C es de 1920 [Lb*in].

Nota: ya que no se menciona la fuerza en el punto A, esta se desprecia y no se tiene en cuenta en los calculos. En la imagen adjunta se puede ver el procedimiento desarrollado.

7 0
3 years ago
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