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nadezda [96]
3 years ago
7

Examples of energy balance: physical education

Physics
1 answer:
mart [117]3 years ago
7 0

Answer:children burn calories to being a student  

Explanation:That mean when a children getting ready to go to high school

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Diana has just been diagnosed with "pre-diabetes," and her doctor has instructed her to watch her intake of sugar. This is easy
lana [24]

Answer:

sugar free

Explanation:

8 0
3 years ago
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A scientist is conducting research to determine how much pressure a dam can withstand. Why are good observations important to hi
Natalija [7]

The things that a scientist should consider while observing the force is the environmental conditions,the force that is expected to act on the dam, the means to contain that force,  and compare different types of designs in accordance with the location of the dam

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3 years ago
A rock with a mass of 8 kg falls straight down from a height of 7 m. What work is done?
fenix001 [56]
F=MA
F=(8 kg)(9.8 m/s)
F= 78.4 N
W=FD
W=(78.4 N)(7 m)
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How this helps
7 0
3 years ago
Calculate curls of the following vector functions (a) AG) 4x3 - 2x2-yy + xz2 2
aleksandr82 [10.1K]

Answer:

The curl is 0 \hat x -z^2 \hat y -4xy \hat z

Explanation:

Given the vector function

\vec A (\vec r) =4x^3 \hat{x}-2x^2y \hat y+xz^2 \hat z

We can calculate the curl using the definition

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\A_x&X_y&A_z\end{array}\right|

Thus for the exercise we will have

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\4x^3&-2x^2y&xz^2\end{array}\right|

So we will get

\nabla  \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z

Working with the partial derivatives we get the curl

\nabla  \times \vec A (\vec r )=0 \hat x -z^2 \hat y -4xy \hat z

6 0
3 years ago
The period P of a pendulum depend on its length , mass as well as the acceleration due to gravity . Use dimensional analysis to
Savatey [412]

Explanation:

Period P has units of seconds (s).

Length has units of meters (m).

Mass has units of kilograms (kg).

Acceleration has units of meters per second squared (m/s²).

Dimensional analysis:

s = √(m / (m/s²))

Therefore:

P = k √(L/g)

where k is a dimensionless constant.

6 0
3 years ago
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