The time interval in which the larger force act is 1.1 seconds.
<h3>What is impulse?</h3>
The impulse produced by an object is determined from the product of force and time of force of the object.
The impulse experienced by an object is the product of mass and velocity of the object or simply the impulse experienced by object is equal to change in the momentum of an object.
J = Ft
where;
- F is the applied force
- t is the time of force acting
The magnitude of the force that produce impulse of 3 Ns for 3.2 seconds is calculated as;
F = J/t
F = (3 Ns) / (3.2 s)
F = 0.94 N
The magnitude of the force that is three times larger is calculated as;
F₂ = 3 x 0.94 N
F₂ = 2.82 N
The time interval of the larger force is calculated as;
t₂ = J/F₂
t₂ = 3 / 2.82
t₂ = 1.1 seconds
Thus, the impulse experienced by an object is a function of force and time of force action.
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Answer: 
Explanation:
Given
Length of the race track 
the radius of curvature of the track 
time taken to run on track is 
Speed of runner is
Centripetal acceleration is
Main answer- the velocity of 2.2kg ball is 12.566m/s
supporting answer- In circular motion the velocity is termed as angular velocity
Angular velocity represents the rate of variation of an object's position angle with respect to time.
W =theta/ time
W = length of the arc/ radius of circle × time
body of the answer-2πr/r×t =2π/t
2×π/ 0.5 = 12.566 m/s
final answer- hence the velocity of ball is revolving is 12.566 m/s
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Answer:
b) the refracted ray has an angle of 90 degrees
Explanation:
The angle of incidence is measured with respect to the normal separation of the media. The critical angle for total internal reflection occurs is:
Here 
and 
are the refractive index of the mediums. This equation is an application of Snell's law, for the case where the refracted ray has an angle of 
.
