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DerKrebs [107]
3 years ago
8

In an arcade game a 0.117 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releas

ing it. If the spring has a spring constant of 194 N/m and is compressed from its equilibrium position by 7 cm, find th
Physics
1 answer:
Illusion [34]3 years ago
3 0

Find the speed with which the disk slides across the surface

Answer:

\boxed{2.85 m/s}

Explanation:

The Potential energy of spring is transformed to kinetic energy hence

0.5kx^{2}=0.5mv^{2}\\kx^{2}=mv^{2}\\v=\sqrt{\frac {kx^{2}}{m}}

Here k is the spring constant, x is the extension of spring, v is the velocity of disk and m is the mass of the disk.

Substituting 0.117 Kg for m, 194 N/m for k and 0.07 m for x then

v=\sqrt{\frac {194\times 0.07^{2}}{0.117}}=2.850401081 m/s\approx \boxed{2.85 m/s}

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A kickoff sends a football with an initial velocity of 25 m/s at an angle of 50
eduard

Answer:

The x-component of the velocity is 16.07 m/s

The y-component of the velocity is 19.15 m/s

Explanation:

Given;

initial velocity of the football, u = 25 m/s

angle of projection, θ = 50⁰

The x-component of the velocity (horizontal component) is given as;

V_x = Vcos(50^0)\\\\V_x = 25 \ m/s \ \ \times \ \ 0.6428\\\\V_x = 16.07 \ m/s

The y-component of the velocity (vertical component) is given as;

V_y = Vsin(50^0)\\\\V_y = 25 \ m/s \ \ \times \ \ 0.766\\\\V_y = 19.15 \ m/s

7 0
3 years ago
Ondrea could drive a Jetson's flying car at a constant speed of 540.0 km/hr across oceans and space, approximately how long woul
Tcecarenko [31]

Answer:

The time taken in years is   x = 125 \  years

Explanation:

From the question we are told that

   The  speed is  v  = 540.00 \ km /hr  =  \frac{540 *1000}{3600} =  150\  m/s

    The distance from the sun to Pluto is  d =  5.9*10^{9} \  k m =  5.9*10^9 * 1000 =  5.9*10^{12} \  m

Generally the time  taken is mathematically represented as

     t =  \frac{d}{v}

=>   t = \frac{5.9*10^{11}}{150}

=>   t =  3.933*10^{9}

Converting to years

   1 year  \to  3.154*10^7 \  s

    x \  years  \to 3.933*10^{9}

=>  x = \frac{ 3.933*10^{9} * 1 }{ 3.154 *10^7}

=>    x = 125 \  years

7 0
3 years ago
Plzz answer this question correctly
Lelechka [254]

Answer:

I'm not sure sorry.... shshsjsk

6 0
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Identify which objects will accelerate to the left, which will accelerate to the right,and those that will not accelerate. Optio
Licemer1 [7]

Answer:

The situation given in option A and B are examples for moving an object toward left side while the option C and option D are examples for moving an object toward right side. Option B will also be an example for not moving the object.

Explanation:

As per the option A statement, the force acting towards left is greater than the force acting toward right side. So the net force will be towards the direction having maximum magnitude. Thus, the box will move toward left side in option A. The same situation arises for the object in option B. But here the difference in the forces is only 1 N, so the change in the position of the object will be very less. Thus it may look like there is no acceleration in the box of option B.

Similarly, the force acting on the objects given in option C and D have magnitude greater towards the right side than towards the left side.  So these two will be accelerated toward the right side.

3 0
3 years ago
6.P.2.1 Matter: Properties and Changes Notes
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Answer:

The __law__ conservation

of state that either energy may produced nor destroyed

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