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Luda [366]
3 years ago
5

Becky invests £5000 for 2 years in a bank account.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

£300

Step-by-step explanation:

We apply the formula for Simple Interest:

I = \frac{P * R * T}{100}

where P = Principal

R = Rate of interest

T = Time elapsed (in years)

We are given that P = £5000, R = 3%, T = 2 years

The interest after 2 years will be:

I = \frac{5000 * 3 * 2}{100} \\\\\\I = \frac{30000}{100}

I = £300

The interest Becky will get after 2 years will be £300.

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The research of Eich and Metcalf would suggest that if you were really happy when you were learning math, you should be ________
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Read 2 more answers
F(x) = 12 + x<br> X<br> f(x)<br> -3<br> -1<br> 0<br> 4<br> 6
katen-ka-za [31]

9514 1404 393

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  (-3, 9), (-1, 11), (0, 12), (4, 16), (6, 18)

Step-by-step explanation:

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3 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

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3 years ago
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