Answer:
0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 3 cm and a standard deviation of 0.04 cm.
This means that 
What is the probability that a bolt has a length greater than 2.96 cm?
This is 1 subtracted by the p-value of Z when X = 2.96. So
has a p-value of 0.1587.
1 - 0.1587 = 0.8413
0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.
A.9×6x - ( 9×2)=
64x-18 = 0
64x=18
x=18/64 =1/3 =0.3
B. 64x+18=0
64x= -18
x =-18/64
x= -1/3
x = -0.3
Answer:
D but read below.
Step-by-step explanation:
I take it that the symbol ~ stands for similar. If that is so, then the answer you want is AA, because if 2 angles in a triangle are equal, then all 3 are. So if any 2 equal angles in one triangle are equal to 2 angles in another, then the two triangles are similar.
Answer:
The minimum number of assignment statements needed is 5
Step-by-step explanation:
To write the algorithm, we apply the strategy of interchanging the values of variables in the assignment statements.
Assume "tmp" is the new variable, let assign tmp to w
The algorithm is:
Procedure exchange (w,x,y,z: integers)
tmp := w
w := x
x := y
y := z
z := tmp
return (w,x,y,z)
end
From the algorithm, it is obvious that there will be a minimum of 5 assignment statements needed.
