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3 years ago

14

You and your dog go for a walk to the park. On the way, your dog takes many side trips to chase squirrels, mark its territory on

a tree, and smell other dogs. When you arrive at the park, do you and your dog travel the same distance?

1 answer:

mr Goodwill [35]3 years ago

8 0

Answer:

yes because its not how much you walk if it is the same distance to the park, then yes. You walked the same distance to the park, however the dog ran more around, you were possibly following the dog so... yea.

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4a3b5 − 16a5b2 + 12a2b3 factored form

Natali [406]

Answer:

$4a^2 b^2( ab^3 - 4a^3 + 3b)$

Step-by-step explanation:

$4a^3 b^5 - 16a^5 b^2 + 12a^2 b^3$

Factor:

- > $4a^2 ab^2 b^3 - 16a^2 a^3 b^2 + 12a^2 b^2 b$

-> $4a^2 ab^2 b^3 + 4 * 4a^2 a^3 b^2 + 3 * 4a^2 b^2 b$

-> factor out $4a^2 b^2$

-> $4a^2 b^2( ab^3 - 4a^3 + 3b)$

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1 year ago

Which of the following graphs represents the solution set for y less than -2x -4

Alona [7]

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3 years ago

Solve using the Pythagorean identity<br>

Lynna [10]

<h3> $\bold{Sin\theta_{1}=-\frac{4}{5}}$ </h3>

Answer:

Solution given

Cos $\displaystyle \theta_{1}=\frac{3}{5}$

consider Pythagorean theorem

$\bold{Sin²\theta+Cos²\theta=1}$

Subtracting $Cos²\theta$ both side

$\displaystyle Sin²\theta=1-Cos²\theta$

doing square root on both side we get

$Sin\theta=\sqrt{1-Cos²\theta}$

Similarly

$Sin\theta_{1}=\sqrt{1-Cos²\theta_{1}}$

Substituting value of $Cos\theta_{1}$

we get

$Sin\theta_{1}=\sqrt{1-(\frac{3}{5})²}$

<h3>Solving numerical</h3>

$Sin\theta_{1}=\sqrt{1-(\frac{9}{25})}$

$Sin\theta_{1}=\sqrt{\frac{16}{225}}$

$Sin\theta_{1}=\frac{\sqrt{2*2*2*2}}{\sqrt{5*5}}$

$Sin\theta_{1}=\frac{4}{5}$

Since

In IVquadrant sin angle is negative

$\bold{Sin\theta_{1}=-\frac{4}{5}}$

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2 years ago

Read 2 more answers

Let a4+a8+a12+a16=224. Find the sum of first 19 term in sequence.

Tomtit [17]

Without knowing anything about the sequence, this is impossible to answer. But suppose the sequence is arithmetic, in which case each term differs by some constant $k$ :

$a_2=a_1+k$

$a_3=a_2+k=a_1+2k$

$a_4=a_3+k=a_1+3k$

$\ldots$

$a_n=a_{n-1}+k=a_1+(n-1)k$

Then we can write

$a_4+a_8+a_{12}+a_{16}=4a_1+36k=224\implies a_1+9k=56$

and from the formula above, we see this means the 10th term in the sequence is $a_{10}=56$ . But that's all the specific info we can gather about such an arithmetic sequence. If we set the first term to be some unknown $a_1=a$ , then the sum of the first 19 terms in the sequence would be

$\displaystyle\sum_{n=1}^{19}a_n=\sum_{n=1}^{19}\big(a+(n-1)k\big)=19a+k\sum_{n=1}^{18}n=19a+171k$

If we knew one more term in the sequence, we could determine the value of $k$ and derive the value of $a$ (if the first term $a_1$ is not immediately given), and then go on to find an exact numeric value for the sum.

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3 years ago

Am I right vote you brainiest

ryzh [129]

Answer:

false

Step-by-step explanation:

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