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Talja [164]
2 years ago
14

You and your dog go for a walk to the park. On the way, your dog takes many side trips to chase squirrels, mark its territory on

a tree, and smell other dogs. When you arrive at the park, do you and your dog travel the same distance?
Mathematics
1 answer:
mr Goodwill [35]2 years ago
8 0

Answer:

yes because its not how much you walk if it is the same distance to the park, then yes. You walked the same distance to the park, however the dog ran more around, you were possibly following the dog so... yea.

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David wants to hang a mirror in his room. The mirror and frame must have an area of 8 square feet. The mirror is 2 feet wide and
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Represent the thickness of the frame by x. Framing the mirror will increase both its length and width by 2x. The area of the mirror with the frame is the product of the length and width which can mathematically be expressed as,
                                 
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The equation above can be simplified into 4x^2 + 10x -2 = 0. This equation can still be further simplified by dividing it by 2. However, it will give an answer which is not found on the choices. Thus, the answer is the third choice. 
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kirza4 [7]

Answer:

I would go with letter F because it's most reasonable.

Step-by-step explanation:

Each row has 4 squares.

Since three are circled it is 3/4.

So 3/4 divided by 4 is 3/16.

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3 years ago
If g is the midpoint of FH find Fg
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If G is the midpoint of FH find FG

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4 0
2 years ago
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The LCM will be the values that are common to both factors. From the given values the LCM will be 2² * 3² * 5

<h3>Least common multiple</h3>

LCM is the lowest number that can divide all other numbers given in an  expression.

Given the prime factorizations 2² * 3² * 5 and 2*3*5. The LCM will be the values that are common to both factors.

From the given values the LCM will be 2² * 3² * 5

Learn more on LCM here: brainly.com/question/233244

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8 0
2 years ago
The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:
deff fn [24]

Step-by-step explanation:

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again the another form of circle is,

{x}^{2}  +  {(y - k)}^{2}  = 21 \\ or \:  {x}^{2}  + {y}^{2}  - 2ky +  {k}^{2}  - 21 = 0 \\ by \: compairing \:it \: with \:  \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get  \\ g = 0 \\f =  - k \\ c =  {k}^{2}  - 21

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-k=-3

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3 years ago
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