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Yuki888 [10]
3 years ago
6

Maria claims that any fraction between 1/5 and 1/7 on a number line must have a denominator that is 6.Enter a fraction that show

s Maria's claim is incorrect A. 6/35 B.13/70 C. 9/35 D.16/70 please help me
Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

Answer

A or B

Step-by-step explanation:

the lowest is 1/7 = 5/35 = 10/70

the highest is 1/5 = 7/35 = 14/70

so answer A and B are OK

C and D are out of range

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first 5 syllables

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25 (a square) - 4 (b square) + 28bc - 49 (c square)
LUCKY_DIMON [66]

Answer:

(5a - [2b - 7c]) and (5a + [2b + 7c])

Step-by-step explanation:

Factor 25a^2 - 4b^2 + 28bc - 49c^2.

Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable.  Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:

- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or

                                        -(2b - 7c)^2.

Thus, the original  25a^2 - 4b^2 + 28bc - 49c^2  looks like:

                               [5a]^2 - [2b - 7c]^2

Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b).  Applying this pattern to the problem at hand, we conclude:

Thus,   [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])

8 0
3 years ago
Two vertices of a right triangle have coordinates ( 9 , 1 ) and (;6 , - 1 ) Select each ordered pair that could be the coordinat
Serjik [45]

Option A: (9,-1) is the third vertex

Option B: (6,1) is the third vertex.

Explanation:

The two vertices of the right triangle are (9,1) and (6,-1)

The third vertex of the right triangle can be determined by plotting the points in the graph.

Option A: (9,-1)

By plotting the points (9,1), (6,-1) and the third vertex (9,-1) in the graph, the the hypotenuse of the triangle passes through the vertices (9,1) and (6,-1)

The legs of the triangle passes through the vertices (9,1), (9,-1) and (6,-1), (9,-1)

Hence, the third vertex (9,-1) forms a right triangle.

Therefore, Option A is the correct answer.

Option B: (6,1)

By plotting the points (9,1), (6,-1) and the third vertex (6,1) in the graph, the hypotenuse of the triangle passes through the vertices (9,1) and (6,-1)

The legs of the triangle passes through the vertices (9,1), (6,1) and (6,1) , (6,-1)

Hence, the third vertex (6,1) forms a right triangle.

Therefore, Option B is the correct answer.

Option C: (1,-1)

By plotting the points (9,1), (6,-1) and the third vertex (1,-1) in the graph, we can see that the three vertices does not make a right angled triangle.

Hence, the third vertex (1,-1) does not form a right triangle.

Therefore, Option C is not the correct answer.

Option D: (6,9)

By plotting the points (9,1), (6,-1) and the third vertex (6,9) in the graph, we can see that the three vertices does not make a right angled triangle.

Hence, the third vertex (6,9) does not form a right triangle.

Therefore, Option D is not the correct answer.

5 0
3 years ago
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