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Zinaida [17]
3 years ago
11

Prove that for every pair of integers m and n, if n − m is even, then n 2 − m is also even. (You may freely use the fact that th

e sum of two odd numbers is even, that the sum of an odd number and an even number is odd, the product of an odd and an even is even, etc.)
Mathematics
1 answer:
Romashka [77]3 years ago
7 0

Answer with Step-by-step explanation:

We are given that  n and m are two integers

We have to prove that if n-m is even , then n^2-m is also even.

We know that sum of two odd numbers is even.Sum of an odd number and even number is odd.

Product of an odd number and even number is even.

Case 1.Suppose m and n are both even n=4 , m=2

4-2=2

(4)^2-2=14 =Even

Case 2.Suppose m odd and n odd

n=9,m=5

9-5=4

(9)^2-5=76=Even

Hence, proved.

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3 years ago
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2 years ago
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Novosadov [1.4K]

Answer:

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Step-by-step explanation:

Let the common multiplier of the given ratios be x.

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4 0
3 years ago
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2 years ago
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Katarina [22]

Answer:

(2,4)

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