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stiv31 [10]
3 years ago
11

EXTREMELY URGENT GEOMETRY! 15 POINTS! PLEASE HELP

Mathematics
1 answer:
zhenek [66]3 years ago
7 0

Answer:

20.3 units

Step-by-step explanation:

AB/CB = BD/AB

9/CB = 4/9

CB = 9×9/4

CB = 81/4 = 20¼ units

20.25 (20.3 units correct to 1 dp)

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A cable that weighs 8 lb/ft is used to lift 750 lb of coal up a mine shaft 500 ft deep. Find the work done. Show how to approxim
Annette [7]

Answer:

13.8 × 10⁵ lb/ft

Step-by-step explanation:

Suppose the distance(ft) below the top of the shaft is represented by x

The weight of the cable = 8 lb/ft

Weight of the coal to be lifted from mine = 750 lb

Recall that:

The work done by a force f to move an object through a distance x can be expressed as:

W = force (f) × displacement (x)

So, the force implies the total weight which should be lifted at any height x

f(x) = 750 + 8x

Using Riemann sum

where; the coal is lifted from x = 0 to x = 500 i.e. [a,b] = [0,500]

Dividing the interval into n subintervals

\Deltax = \dfrac{b -a }{n}

\Deltax = \dfrac{500- 0 }{n}

Suppose [x_{i-1},x_i ] to represent the i^{th} subinterval, then the work done can be estimated as:

W_i = f(x_i) \Delta x

W_i =(750 + 8x_i) \Delta x

Therefore; the total work done in between all the n subintervals is:

W = \sum \limits ^n_{i=1} W_1

W = \sum \limits ^n_{i=1} f(x_i) \Delta x

W = \sum \limits ^n_{i=1}(750 +8x_I)\Delta x

Therefore;

dW = f(x) dx

\int \ dW = \int \ f(x) \ dx where x ranges from 0 to 500

W = \int ^{500}_{0} \ 750 + 8x \ dx

W =\bigg  [750x + 4x^2 \bigg ]^{500}_{0}

W =\bigg  [750(500) + 4(500)^2-0 \bigg ]

W = 375000 + 1000000

W = 1375000

Thus; the total work done W = 13.8 × 10⁵ lb/ft

5 0
3 years ago
Dinner $50 with 18% tip
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18 percent of $50 is $9.


3 0
3 years ago
Read 2 more answers
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Natalija [7]

Answer:

Step-by-step explanation:

This is a test of the mean difference between 2 independent groups or populations.

Let μ1 be the mean annual bonus of Company A's employees and μ2 be the mean annual bonus of Company B's employees.

The random variable is μ1 - μ2 = difference in the mean annual bonus of Company A's employees and the mean annual bonus of Company B's employees

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 ≤ μ2 H0 : μ1 - μ2 ≤ 100

The alternative hypothesis is

H1 : μ1 > μ2 H1 : μ1 - μ2 > 100

This is a right tailed test because of the inequality sign at the alternative hypothesis. We need to take samples of annual bonuses from both company's employees and find the averages. Then we would determine the test statistic as well as the p value. We would use the p value with the level of significance to make decisions

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2 years ago
Given that f(x) = 2x − 5, find the value of x that makes f(x) = 15.
nexus9112 [7]
2x-5=15
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3 years ago
Write the equation of a line that is perpendicular to y=-4/3x+9 and goes through (8,-5). Do not use spaces in your answer. Enter
liq [111]

Answer:

y=3/4x-11

Step-by-step explanation:

When a line is perpendicular to another line, their slope is the opposite reciprocal of that. So in this case, the slope of the perpendicular line would be positive 3/4. Next, plug in the points (8,-5) in the y=mx+b formula along with the new slope. In conclusion, the new point slope formula is y=3/4x-11.

Hope this helps! :)

8 0
2 years ago
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