Answer:
Step-by-step explanation:
<u>Equation of a Circle</u>
A circle of radius r and centered on the point (h,k) can be expressed by the equation
We are given the equation of a circle as
Note we have corrected it by adding the square to the y. Simplify by 3
Complete squares and rearrange:
We can see that, if r=4, then
Or, equivalently
There are two solutions for 
:
Keeping the positive solution, as required:
(<span>used with a singular verb</span><span>) the systematic treatment of magnitude,relationships between figures and forms, and relations betweenquantities expressed <span>symbolically</span></span>
Answer:
Most of the time you can go on a website that can cauculate it.
Step-by-step explanation:
How to cauculate the MAD:
Take each number in the data set, subtract the mean, and take the absolute value. Then take the sum of the absolute values. Now compute the mean absolute deviation by dividing the sum above by the total number of values in the data set. Finally, round to the nearest tenth.
Given :
Devin is buying 2 concert tickets. The concert tickets have a regular price of $40 each.
Devin has a coupon that gives a 5% discount off of the regular price of the tickets. He will then pay a 10% purchasing fee on the discounted price of the tickets.
To Find :
Devin's total cost of the two tickets after the discount and the fee.
Solution :
Discount on price, D = 40×0.05 = $2 .
Price of product after discount, P = $( 40 - 2 ) = $38 .
Now, total price after adding purchasing fee is :
T = P + (P×0.10)
T = 38 + (38×0.10)
T = 38 + 3.8
T = $41.8
Therefore, Devin's total cost of the two tickets after the discount and the fee is $41.8 .
Hence, this is the required solution.
Answer: About 191 students scored between a 60 and an 80.
Step-by-step explanation:
Given : A set of 200 test scores are normally distributed with a mean of 70 and a standard deviation of 5.
i.e. 
and 
let x be the random variable that denotes the test scores.
Then, the probability that the students scored between a 60 and an 80 :
The number of students scored between a 60 and an 80 = 0.9544 x 200
= 190.88 ≈ 191
Hence , about 191 students scored between a 60 and an 80.
