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Sati [7]
3 years ago
11

1-Calcular la velocidad de un móvil que puede recorrer 108 Km en 3h, utilizando las ecuaciones aprendida.

Physics
1 answer:
Ede4ka [16]3 years ago
5 0

Answer:

L*W *H

Explanation:

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The oscillating electric field in a plane electromagnetic wave is given by <img src="https://tex.z-dn.net/?f=%7B50%5Csin%20%28%5
Scorpion4ik [409]

Here, we are given with:

{:\implies \quad \longrightarrow \begin{cases}\sf E_{0}= 50\: V/m\\ \sf \nu = 2\times 10^{7}Hz\end{cases}}

(a) So now, we can thus obtain

{:\implies \quad \sf \omega =2\pi \nu}

{:\implies \quad \sf \omega =2\pi (2\times 10^{7})}

{:\implies \quad \boxed{\bf{\omega = 4\pi \times 10^{7}\: s^{-1}}}}

Now, finding \lambda

{:\implies \quad \sf \lambda =\dfrac{c}{\omega}=\dfrac{3\times 10^{8}}{4\pi \times 10^{7}}}

{:\implies \quad \boxed{\bf{\lambda \approx 2.39\:m}}}

Now, finding k

{:\implies \quad \sf k=\dfrac{2\pi}{\lambda}=\dfrac{200\pi}{239}}

{:\implies \quad \boxed{\bf{k\approx 2.63\:m^{-1}}}}

Thus, expression for the electric field is:

{:\implies \quad \boxed{\bf{E=50\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)}}}

(b) Now, here

{:\implies \quad \sf B_{0}=\dfrac{E_{0}}{c}=\dfrac{50}{3\times 10^{8}}}

{:\implies \quad \boxed{\bf{B_{0}\approx 16.67×10^{-7}\:T}}}

Thus, expression for the magnetic field:

{:\implies \quad \boxed{\bf{B_{y}=16.67\times 10^{-7}\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)\:T}}}

(c) The electromagnetic wave propagates along Z-axis

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2 years ago
I will give brainliest) According to Newton's second law of motion, when an object is acted on by an unbalanced force, how will
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Exercising at a level thats beyond your regular daily activities is
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Healthy to get better at your daily activities but harmful to your body if you overdo it
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2. Only power tools with a 3-wire cord with
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I think it is false
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andreyandreev [35.5K]

Answer:

The offspring is homozygous for eye color.

Explanation:

Brown eyes is the shared allele of both parents (meaning homozygous) and an allele for hair type was not inherited from only one parents but from both however will recieve the dominant trait. (This is my best guess; I haven't studied this in awhile though)

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