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Sati [7]
3 years ago
11

1-Calcular la velocidad de un móvil que puede recorrer 108 Km en 3h, utilizando las ecuaciones aprendida.

Physics
1 answer:
Ede4ka [16]3 years ago
5 0

Answer:

L*W *H

Explanation:

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If you drop a silver dollar off a building and it hits the ground in 10 seconds, how fast was the coin going just before it hit?
Illusion [34]
Objects in free fall, disregarding terminal velocity, accelerate at 9.8(m/s)/s. so for every second it was falling, it gained 9.8m/s in speed. 9.8 * 10 = 98m/s
4 0
3 years ago
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A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5
masya89 [10]

Answer:

39 m/s

Explanation:

7 0
2 years ago
Choose all that apply. Solids, liquids, and gases can be distinguished by their:
vodomira [7]
I believe its by there shape
8 0
3 years ago
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A lead nucleus is spherical with a radius of about 7 ✕ 10⁻¹⁵ m. The nucleus contains 82 protons (and typically 126 neutrons). Be
Komok [63]

Answer:

∈=3.1584x10^{26} \frac{V}{m}

Explanation:

Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus

∈=\frac{P}{E_{o}}

The P is the charge density and 'Eo' is the constant of permittivity in free space

to find P

P=\frac{q}{V}

V=\frac{4}{3}*\pi*r^3

V=\frac{4}{3}\pi*(7x10^{-15})^3

V=2.932x10^{-14} m^3

P=\frac{82C}{2.932x10^{-14}m^3}=2.7965x10^{15} \frac{C}{m^3}

So replacing

∈=\frac{2.7965x10^{15}\frac{C}{m^3}}{8.8542x10^{-12}\frac{C^2}{N*m^2}}

∈=3.1584x10^{26} \frac{V}{m}

3 0
3 years ago
The melting point of a solid is 90.0C. What is the heat required to change 2.5 kg of this solid at 30.0C to a liquid? The specif
Neko [114]

Hey again!

Ok..

Now... The melting Point of this solid is 90°C.

Meaning That as soon as it gets to this temp... It STARTS Melting.

So at that temp... It still has some solid parts in it.

You can say its a Solid Liquid Mixture.

Additional Heat being applied at that point is not raising the temperature;rather its used in breaking the bonds in the solid. This is the Fusion stage.

After Fusion...It'd then Be a Pure Liquid with no solids in it.

So

Q'=MC∆0----- This is the heat needed to take the solid's temp from 30°c - 90°c

Q"=ml ----- This is the heat used in breaking the bonds holding the solids in the solid-liquid phase.

So

Q= Q' + Q"

Q= mc∆0 + ml

∆0 = 90°c - 30°c = 60°c

Q= 2.5(390)(60) + (2.5)(4000)

Q=6.9 x 10⁴Joules

7 0
3 years ago
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