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Dahasolnce [82]
3 years ago
7

A force of F = (2.00ˆi + 3.00ˆj) N is applied to an object that is pivoted about a fixed axle aligned along the z coordinate axi

s. The force is applied at the point r = (4.00ˆi + 5.00ˆj) m.
Find:

(a) the magnitude of the net torque about the z axis

(b) the direction of the torque vector τ
Physics
1 answer:
Vladimir [108]3 years ago
5 0

Explanation:

It is given that,

Force applied to object, F=(2i+3j)\ N

Position, r=(4i+5j)\ m  

(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :

\tau=F\times r

\tau=(2i+3j) \times (4i+5j)

\tau=\begin{pmatrix}0&0&-2\end{pmatrix}

or

\tau=(-2k)\ N-m

The torque is acting in -z axis.

(a) The magnitude of torque is given by :

|\tau|=\sqrt{(-2)^2}

|\tau|=2\ N-m

Hence, this is the required solution.

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¿Que trabajo realizas cuando subes una bolsa de la compra cuya masa es 4,5 kg desde el suelo hasta una mesa de 90 cm de altura?¿
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a boy throw a ball upward from the top of a cliff 73m high.Calculate the time in which ball will fall on the ground and the velo
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3 0
3 years ago
Assume a rectangular strip of a material with an electron density of n=5.8x1020 cm-3. The strip is 8 mm wide and 0.8 mm thick an
vampirchik [111]

Answer: I = 111.69 pA

Explanation: The hall effect is all about the fact that when a semiconductor is placed perpendicularly to a magnetic field, a voltage is generated which could be measured at right angle to the current path. This voltage is known as the hall voltage.

The hall voltage of a semiconductor sensor is given below as

V = I×B/qnd

Where V = hall voltage = 1.5mV =1.5/1000=0.0015V

I = current =?,

n= concentration of charge (electron density) = 5.8×10^20cm^-3 = 5.8×10^20/(100)³ = 5.8×10^14 m^-3

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By slotting in the parameters, we have that

0.0015 = I × 5/5.8×10^14 × 1.609×10^-19×0.0008

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I = (0.0015 × 7.446×10^-8)/5

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I = 111.69 pA

3 0
3 years ago
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