Answer:112.82 m/s
Explanation:
Given
range of arrow=68 m

as the arrow travels it acquire a vertical velocity 

-------1
Range is given by
R=ut
where u=initial velocity


substitute the value of t in eqn 1

--------2
and 

substitute it in 2


u=112.82 m/s
Answer:
B is the answer a force is a push or pull
C.
hope that helped you!!!
Answer:
48.51ms / 174.6 km/h
Explanation:
y = 1/2 x g x t^2 v = g x t
when y = 120m
120 = 1/2 x 9.8 x t^2
t^2 = 24.49
t = 4.95s
when t = 4.95s
v = 9.8 x 4.95
v = 48.51 m/s = 174.6 km/h
I'd say its realistic. But I don't really know that sry