Answer:
r = 5.335 meters
Explanation:
Given that,
Charge 1,
Charge 2,
Force of attraction between two charges, F = 6 N
The force of attraction between two charges is given by :
, r is the separation between two charges
r = 5.335 m
So, the separation between two charges is 5.335 meters. Hence, this is the required solution.
Answer:
The force of repulsion between the two balls will increase
Explanation:
The electrostatic force between two charged objects is given by
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the distance between the centres of the two objects
We see that the magnitude of the force is directly proportional to the charges on the two objects. in this problem, we have two positively charged balls (so, there is a force of repulsion between them, since like charges repel each other and unlike charges attract each other), and the positive charge in one of them is slowly increased: this means that either or
in the formula is increasing, and so the magnitude of the force is increasing.
The density of a substance is the ratio of its mass to its volume. So whatever volume you have (call it ), the density
is computed by