The Moon s escape speed will be smaller than Earth's.
The minimum speed that is required for an object to free itself from the gravitational force exerted by a massive object.
The formula of escape speed is
where
v is escape velocity
G is universal gravitational constant
M is mass of the body to be escaped from
r is distance from the center of the mass
we can say that,
Escape speed depends on the gravity of the object trying to hold the spacecraft from escaping.
we know that,
The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second.
since, v ∝ g
The Moon s escape speed will be smaller than Earth's.
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Answer:
B. 1500 kg*m/s
Explanation:
Momentum p = m* v
In any type of collision, the total momentum is preserved!
The total momentum before and the total momentum after the collision is the same. We know the mass and speed after the collision so we can calculate the total momentum.
p1 + p2 =
m1*v1 + m2*v2
m1 = me = 300 kg
v1 = 3 m/s
v2 = 2 m/s
Substitute the given numbers:
300*3 + 300+2
900 + 600
1500 kg*m/s, which is answer B.
Of the following...?? Is there more to this question? :)
Explanation:
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M1U1 + M2V2 = (M1+M2)V, where M1 is the mass of the moving car, M2 is the mass of the stationary car, U1 is the initial velocity, and V is the common velocity after collision.
therefore;
(1060× 16) + (1830 ×0) = (1060 +1830) V
16960 = 2890 V
V = 5.869 m/s
The velocity of the cars after collision will be 5.689 m/s