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jonny [76]
3 years ago
13

Match each wave characteristic to its description.

Physics
2 answers:
Cerrena [4.2K]3 years ago
5 0

Answer :

Frequency - The number of cycles of wave per second

Wavelength - The distance between adjacent crests or troughs

Amplitude - The height of wave from its equilibrium position

Explanation :

Frequency - The number of cycles of wave per second

Formula of frequency

f=\dfrac{1}{T}

Wavelength - The distance between adjacent crests or troughs

Formula of wavelength

f=\dfrac{c}{\lambda}

Amplitude - The height of wave from its equilibrium position

AVprozaik [17]3 years ago
3 0
Wavelength goes with- the distance between
amplitude- the height
frequency- the number of cycles. I just answered this on plato and got it right.
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The speed of the animals is 1.64m/s.

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Let us work with variables and call the mass of the two rats m_1 and m_2,  and the length of the rod L.

Using the law of conservation of energy, which says the potential energies of the rats must equal their kinetic energies, we know that when the rod swings to the vertical position,

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$(m_1 -m_2)g\frac{L}{2} = \frac{1}{2}(m_1+m_2)v^2$,

solving for v, we get:

$\boxed{v = \sqrt{\frac{(m_1 -m_2)gL}{(m_1+m_2)}} }$

Putting in the values for m_1, m_2, g, and L we get:

$v = \sqrt{\frac{(0.450kg -0.220kg)(9.8m/s^2)(0.8m)}{(0.450kg+0.220kg)}} $

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Therefore, as the rod swings through the vertical position , the speed of the rats is 1.64 m/s.

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Find how much work ∆<em>W</em> is done by the motor in lifting the elevator:

<em>P</em> = ∆<em>W</em> / ∆<em>t</em>

where

• <em>P</em> = 45.0 kW = power provided by the motor

• ∆<em>W</em> = work done

• ∆<em>t</em> = 20.0 s = duration of time

Solve for ∆<em>W</em> :

∆<em>W</em> = <em>P</em> ∆<em>t</em> = (45.0 kW) (20.0 s) = 900 kJ

In other words, it requires 900 kJ of energy to lift the elevator and its passengers. The combined mass of the system is <em>M</em> = (<em>m</em> + 490.0) kg, where <em>m</em> is the mass of the elevator alone. Then

∆<em>W</em> = <em>M</em> <em>g h</em>

where

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Solve for <em>M</em>, then for <em>m</em> :

<em>M</em> = ∆<em>W</em> / (<em>g h</em>) = (900 kJ) / ((9.80 m/s²) (35.0 m)) ≈ 2623.91 kg

<em>m</em> = <em>M</em> - 490.0 kg ≈ 2133.91 kg ≈ 2130 kg

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