2 years ago

Does the moon control the waves in the ocean?

2 answers:

8 0

Answer:

The moon does not cause the waves but the moons gravitational pull does cause the low and high tides of the ocean. the moon can cause tidal waves which are similar.

konstantin123 [22]2 years ago

7 0

Answer:

no don't think so

Explanation:

JESUS CHRIST controls everything 100IQ

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Find the magnitude of the electric force between the charges 0.12 C and 0.33 C at a separation of 2.5 m. k=8.99×109N⋅m2/C2.

makkiz [27]

Answer:

F= k Q1 Q2 / r^2

plug in the numbers

8 0

2 years ago

150 ml of water is heated with a burning marshmallow From 20 c to 93.5 C

kap26 [50]

93.5 if it’s wrong sorry sis I need my homework done too

7 0

2 years ago

In an experiment, a large number of electrons are fired at a sample of neutral hydrogen atoms and observations are made of how t

kakasveta [241]

Answer:

N = 1036 times

Explanation:

The radial probability density of the hydrogen ground state is given by:

$p(r) = \frac{4r^{2} }{a_{0} ^{3} } e^{\frac{-2r}{a_{0} } }$

$p(\frac{a_{0} }{2} ) = \frac{4(\frac{a_{0} }{2} )^{2} }{a_{0} ^{3} } e^{\frac{-2(\frac{a_{0} }{2} )}{a_{0} } }$

$p(2a_{0} ) = \frac{4(2a_{0}) ^{2} }{a_{0} ^{3} } e^{\frac{-4a_{0} }{a_{0} } }$

$N = 1300\frac{p(2a_{0}) }{p(\frac{a_{0} }{2} )}$

$N = 1300\frac{(2a_{0}) ^{2}e^{\frac{-4a_{0} }{a_{0} } } }{(\frac{a_{0} }{2} )^{2} e^{\frac{-a_{0} }{a_{0} } }}$

$N = 1300(16) e^{-3}$

N = 1035.57

N = 1036 times

6 0

3 years ago

Liquids take the shape of the bottom of their container, while gases take the shape of their entire container. The shape solids

motikmotik

Answer:

...

Explanation:

sigh its not that hard

Any liquid takes form of the shape of the container it goes into.

Gasses take the form of the whole thing because it spreads throughout it.

Solids are already a shape so it cant take the shape of the container if it already has one. yk

4 0

2 years ago

A 50g ball is falling down. As the ball passes a certain distance its potential energy changes for 2J. Calculate this distance.

Paul [167]

potential energy = mass × gravity × height

so, change in potential energy = mass × gravity × change in height

2 = 50 × 10 × Δh

2 ÷ 500 = Δh

Δh = 0.004 m

This distance does depend on the initial velocity of the ball.

8 0

3 years ago