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Trava [24]
3 years ago
13

Does the moon control the waves in the ocean?

Physics
2 answers:
Ray Of Light [21]3 years ago
8 0

Answer:

The moon does not cause the waves but the moons gravitational pull does cause the low and high tides of the ocean. the moon can cause tidal waves which are similar.

konstantin123 [22]3 years ago
7 0

Answer:

no don't think so

Explanation:

JESUS CHRIST controls everything 100IQ

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The suns energy reaches the sun by<br> Conduction<br> Convection<br> Radiation <br> Fusion
amid [387]

Answer:

Radiation

Explanation:

The sun energy reaches us by Radiation.

8 0
3 years ago
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The same wave travels for 2 seconds, what is its frequency?*
sveticcg [70]

Answer:

In waves distance is measured by wave length  and time is measured by frequency or period.

velocity ratio=wave length multiply by frequency.

HENCE, if the same wave travels for 2 econds its frequency will be 2Hz.

Explanation:

8 0
3 years ago
A hill that has a 28.1% grade is one that rises 28.1 m vertically for every 100.0 ml of distance in the horizontal direction. At
Serhud [2]

Answer:

\theta=15.70^\circ

Explanation:

A right triangle is formed, in which the vertical elevation is the opposite cathetus and the horizontal distance is the adjacent cathetus, since we know these two values, we can calculate the angle of inclination using the definition of tangent:

tan\theta=\frac{opp}{adj}\\\theta=arctan(\frac{opp}{adj})\\\theta=arctan(\frac{28.1m}{100m})\\\theta=15.70^\circ

6 0
4 years ago
A compound containing sodium and chlorine in a binary ionic compound would be named
elena55 [62]

Answer:sodium chloride.

Explanation:

6 0
3 years ago
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Col. John Stapp led the U.S. Air Force Aero Medical Laboratory's research into the effects of higher accelerations. On Stapp's f
Lerok [7]

Answer:

A.a=203.14\ \frac{m}{s^2}

B.s=397.6 m

Explanation:

Given that

speed  u= 284.4 m/s

time t = 1.4 s

here he want to reduce the velocity from 284.4 m/s to 0 m/s.

So the final speed v= 0 m/s

We know that

v= u + at

So now by putting the values

0 = 284.4 -a x 1.4     (here we take negative sign because this is the case of de acceleration)

a=203.14\ \frac{m}{s^2}

So the acceleration  while stopping will be a=203.14\ \frac{m}{s^2}.

Lets take distance travel before come top rest is s

We know that

v^2=u^2-2as

0=284.4^2-2\times 203.14\times s

s=397.6 m

So the distance travel while stopping is 397.6 m.

8 0
4 years ago
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