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3 years ago

Does the moon control the waves in the ocean?

Physics

2 answers:

Ray Of Light [21]3 years ago

8 0

Answer:

The moon does not cause the waves but the moons gravitational pull does cause the low and high tides of the ocean. the moon can cause tidal waves which are similar.

konstantin123 [22]3 years ago

7 0

Answer:

no don't think so

Explanation:

JESUS CHRIST controls everything 100IQ

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When looking at liquids in a container, that have layered on one another;

Mashcka [7]

Answer: C. At the bottom

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2 years ago

In a given chemical reaction, the energy of the products is less than the energy of the reactants. Which statements is true for

Inessa05 [86]

Answer:It is an Endothermic reaction

Explanation:

Exothermic reaction

An exothermic reaction is one that releases energy in the form of heat or light.

Endothermic reaction

An endothermic reaction is one that absorbs energy in the form of heat or light.

7 0

2 years ago

Read 2 more answers

David lifts a book 1.2 meters from the floor to the top of his desk. If the book weighed 0.50 kg, what is the gravitational pote

Anika [276]

Answer:

5.886 J

Explanation:

Given:

The mass of the book is, $m=0.5$ kg

Height of lift is, $\Delta h=1.2$ m

Acceleration due to gravity is, $g=9.81$ m/s²

Now, gain in gravitational potential energy is a function of change in position and is given as:

$\Delta PE=mg\Delta h$

Here, $\Delta PE$ is the change in gravitational potential energy.

Plug in 0.5 kg for $m$ , 9.81 for $g$ and 1.2 for $\Delta h$ . Solve for $\Delta PE$

$\Delta PE=0.50\times 9.81\times 1.2=5.886\ J$

Therefore, the gain in gravitational energy of the book is 5.886 J.

7 0

3 years ago

A Chevrolet Corvette convertible can brake to a stop from a speed of 60.0 mi/h in a distance of 123 ft on a level roadway. What

Digiron [165]

Answer:

83.1946504051 m

Explanation:

u = Initial velocity = $60\ mph=\dfrac{60\times 1609.34}{3600}=26.82233\ m/s$

s = Displacement = $123\ ft=\dfrac{123}{3.281}=37.4885705578\ m$

$\theta$ = Angle = $26^{\circ}$

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-26.82233^2}{2\times 37.4885705578}\\\Rightarrow a=-9.5954230306\ m/s^2$

Coefficient of friction

$\mu=-\dfrac{a}{g}\\\Rightarrow \mu=\dfrac{9.5954230306}{9.81}\\\Rightarrow \mu=0.978126710561$

$mg sin\theta - u mg cos\theta = ma\\\Rightarrow a=9.81(sin26-0.978126710561cos26)\\\Rightarrow a=-4.32382\ m/s^2$

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-26.82233^2}{2\times -4.32382}\\\Rightarrow s=83.1946504051\ m$

The stopping distance is 83.1946504051 m

6 0

3 years ago

Can anyone please help me with this one

Vinvika [58]

Ur in k12 ALVA too???

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3 years ago