Answer:
only if you take copper
Explanation:
Any electric current has an associated magnetic field, so a current-carrying conductor is an electromagnet, regardless of what material it is made. ... However, using copper alone will not make a strong electromagnet
Answer:
C. 1) No Change (4 sec) 2) 5.7 sec 3) 2.8 sec 4) No Change (4 sec)
Explanation:
Given that:
Period (T) = 4 s
1) If the mass is doubled.
The period of a pendulum is given by the formula:
where L is the length and g is the acceleration due to gravity.
From the formula, the period does not depend on the mass of the spring therefore if the mass is doubled the period does not change.
2) The string length is doubled
Given that:
if the length is doubled, the new spring length is 2L. Therefore the new period (T1) is given as:
3) The string length is halved
Given that:
if the length is halved, the new spring length is L/2. Therefore the new period (T1) is given as:
4) The amplitude is halved
From the formula, the period does not depend on the amplitude therefore if the amplitude is halved the period does not change.
2(3x - 1) ≥ 4x - 6 Remove the brackets on the left.
6x - 2 ≥ 4x - 6 Subtract 4x from both sides.
6x - 4x - 2 ≥ - 6 combine like terms on the left.
2x - 2 ≥ - 6 Add 2 to both sides
2x ≥ - 6+ 2
2x ≥ -4 Divide by 2
x ≥ - 4/2
x ≥ - 2 answer <<<<<<<<
Check
2(3*-2 - 1) ≥ 4x - 6
2(-6 - 1) ≥ 4(-2) - 6
2(-7) ≥- 8 - 6
- 14 = - 14 and this checks.
Answer:
Vf = 23 m/s
Explanation:
First we need to find the distance covered by the motorcycle 2 when it passes motorcycle 1. Using the uniform speed equation for motorcycle 1:
s₁ = v₁t₁
where,
s₁ = distance covered by motorcycle 1 = ?
v₁ = speed of motorcycle 1 = 6.5 m/s
t₁ = time = 10 s
Therefore,
s₁ = (6.5 m/s)(10 s)
s₁ = 65 m
Now, for the distance covered by motorcycle 2 at the meeting point. Since, the motorcycle started 50 m ahead of motorcycle 2. Therefore,
s₂ = s₁ + 50 m
s₂ = 65 m + 50 m
s₂ = 115 m
Now, using second equation of motion for motorcycle 2:
s₂ = Vi t + (1/2)at²
where,
Vi = initial velocity of motorcycle 2 = 0 m/s
Therefore,
115 m = (0 m/s)(10 s) + (1/2)(a)(10 s)²
a = 230 m/100 s²
a = 2.3 m/s²
Now, using 1st equation of motion:
Vf = Vi + at
Vf = 0 m/s + (2.3 m/s²)(10 s)
Vf = 23 m/s
